2 pulleys 3 masses problems

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Homework Statement
3 equal weights are attached to the ends and in the middle of the rope. We raise the middle weight so that the rope is horizontal and in the middle between the pulleys, and let it go, after which the middle weight is lowered and the weights at the ends are raised.
How far will the middle weight travel before it starts to rise?
Relevant Equations
3 weights -m
2 pulleys
I don't understand if we let go of the middle mass it will move down the y-axis and the two edge masses up. So the tensions will have to be greater than mg for the edge masses to start moving but then when (if) the system stops then the tension will have to be equal to mg. Is that possible? Will the middle weight move up after some time? So, i came to this thoughts.
Is tension force in rope same all the time , does acceleration of middle weight change during time and why would middle weight go up (rise)?
I saw questions like this , but I am little confused about this questions?
 

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Please provide a drawing and a concise statement of the problem. Also according to our rules, to receive help, you need to show some credible effort towards answering the question. How about telling us what you do know and how you would approach this problem? You need to be more specific about what the question is and what confuses you.

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First, think about the equilibrium position. Can you draw that?
Clearly the centre mass will keep descending as long as it is above that position, but when it reaches it the system components have momentum, so will continue on some way. What do you think will happen thereafter?
 
haruspex said:
First, think about the equilibrium position. Can you draw that?
Clearly the centre mass will keep descending as long as it is above that position, but when it reaches it the system components have momentum, so will continue on some way. What do you think will happen thereafter?


In equillibrium x components shoud cancel and y component of resultant tension should be equal to mg.
If i understand good, two end masse will keep going up and then on middle mass will start acting resultant force up. But is tension force constant at the magnitude ?
 
Last edited:
phy_magic said:
In equillibrium x components shoud cancel and y component of resultant tension should be equal to mg.
The tension is at different angles in different places. Where will its y component be mg?
phy_magic said:
If i understand good, two end masse will keep going up and then on middle mass will start acting resultant force up. But is tension force constant at the magnitude ?
No, the tension will keep changing.

Often one can sidestep a lot of details by applying a conservation law. Can you think of one you can use here?
 
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