202,000=32,800e^k*20 - Solve for K

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Homework Help Overview

The problem involves solving for the variable K in the equation 202,000 = 32,800e^(k*20). The context appears to be related to exponential functions and logarithms, possibly within a calculus framework.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to use logarithms to isolate K but expresses uncertainty about the correct application of logarithmic properties. Some participants suggest isolating the exponential term and using natural logarithms (ln) instead of common logarithms. There is also a discussion about the notation of the exponent, with suggestions to clarify the expression e^(20k).

Discussion Status

Participants are actively engaging with the problem, offering guidance on the use of logarithms and clarifying notation. There is no explicit consensus reached, but some productive direction is provided regarding the manipulation of the equation.

Contextual Notes

There is mention of potential confusion regarding the notation of the exponential term, which may affect interpretation. The problem is also noted to be part of a calculus context, although the final steps do not involve calculus directly.

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Homework Statement


Did most the problem, but know I'm stuck here: 202,000=32,800e^k*20

I need to solve for K

The Attempt at a Solution



Log 202,000 = k*20 log 32,000 e

Do you move the e out in front too? I'm not sure, anyway, I'm stuck here. Not sure what to do or even if you use logs to solve for k.
 
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killersanta said:

Homework Statement


Did most the problem, but know I'm stuck here: 202,000=32,800e^k*20

I need to solve for K

The Attempt at a Solution



Log 202,000 = k*20 log 32,000 e

Do you move the e out in front too? I'm not sure, anyway, I'm stuck here. Not sure what to do or even if you use logs to solve for k.

Remember to use "ln" and not "log" for the inverse operation of e^x

So if you isolate the e^x term, it looks more like this:

\frac{202000}{32800} = e^{k*20}

What would you now do to get rid of the exponential issue so you can deal directly with k?

BTW, I assume this is the end of a calculus problem, with the end not involving calculus.
 
berkeman said:
Remember to use "ln" and not "log" for the inverse operation of e^x

So if you isolate the e^x term, it looks more like this:

\frac{202000}{32800} = e^{k*20}

What would you now do to get rid of the exponential issue so you can deal directly with k?

BTW, I assume this is the end of a calculus problem, with the end not involving calculus.

LN(202,000/32800)= K * 20

k = (LN(202,000/32800)/20) = .09089 ?
 
That works for me.

Be advised, though, that most people would read e^k*20

as ek * 20, and not as e20k, as I think you intended. To better show your intent, write that part as e^(20k). Then it's clear what is in the exponent.
 
Mark44 said:
That works for me.

Be advised, though, that most people would read e^k*20

as ek * 20, and not as e20k, as I think you intended. To better show your intent, write that part as e^(20k). Then it's clear what is in the exponent.

Sweet, Thanks... And I will do from now on.
 

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