MHB 210 AP Calculus Exam problem tangent line to curve

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To find the slope of the tangent line to the curve defined by f(x) = -x^2 + 4√x at x = 4, the derivative f'(x) must be calculated. The derivative is f'(x) = -2x + 2/x^(1/2). Evaluating this at x = 4 gives f'(4) = -8 + 2/2 = -7. Therefore, the slope of the tangent line at that point is -7. The correct answer is (E) -7.
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Find the slope of the tangent line to the graph of
$$f(x)=-x^2+4\sqrt{x}$$
at $x=4$

(A) $8-$
(B) $-10$
(C) $-9$
(D) $-5$
(E) $-7$

rewrite as
$f(x)=-x^2+4x^{1/2}$
then
$\dfrac{d}{dx}f(x)=-2x+\dfrac{2}{\sqrt{x}}$
then
$f'(4)=-2(4)++\dfrac{2}{\sqrt{4}}=-8+1=-7\quad (E)$
 
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I edited your post to fix the spoiler. You had the opening tag embedded in a bunch of formatting tags, and the closer had a backslash instead of the forward slash.
 
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