231.13.3.75 top vertex of a regular tetrahedron

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SUMMARY

The discussion focuses on determining the center point R of a unit sphere placed symmetrically atop three other unit spheres centered at O(0,0,0), P(√3,-1,0), and Q(√3,1,0). The height h of the tetrahedron formed by these spheres is calculated using the formula h = (√3/2) * a, where a = 2. The final coordinates for point R are established as (2√3/3, √3).

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karush
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$\tiny{231.13.3.75}$
$\textrm{Imagine $3$ unit spheres
(radius equal to 1) with centers at,}\\$
$\textrm{$O(0,0,0)$, $P(\sqrt{3},-1,0)$ and $Q(\sqrt{3},1,0)$.} \\$
$\textrm{Now place another unit sphere symmetrically on top of these spheres with its center at R.} \\$
$\textrm{a Find the center of R.} \\$
 
Last edited:
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The following post may give you some insight:

http://mathhelpboards.com/challenge-questions-puzzles-28/tetrahedral-stack-spheres-5676.html#post26011
 
View attachment 7108

ok from this base

$\textrm{so if hieght of $h=\frac{\sqrt{3}}{2} a$ and $a=2$ then:}\\$
\begin{align*}\displaystyle
R&=\left(\sec \left(\frac{\pi }{6}\right),\frac{\sqrt{3}}{2} (2)\right)\\
&=\left( \frac{2\sqrt{3}}{3},\sqrt{3}\right)
\end{align*}

OK couldn't find some comprehensive equation for this so eyeballed it...
 

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