290 Expanding this determinant about the the second column....

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SUMMARY

The discussion focuses on expanding a determinant related to a 3x3 matrix involving the variable λ. The specific determinant is calculated as $\left|\begin{array}{ccc}\lambda- 5 & 0 & 4 \\ -12 & \lambda- 1 & 12 \\ -8 & 0 & \lambda- 7\end{array}\right|$, which simplifies to -(\lambda- 1)[(\lambda- 5)(\lambda+ 7)+ 32]. The value "32" is derived from the product of -8 and 4 in the original matrix. The conversation highlights challenges in understanding linear algebra concepts among participants.

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karush
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View attachment 8905
where does 32 (red) come from ?
nevermind looks its (-8)(4)=-32

but will probable have more ? on this example
 

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Expanding on the second column we have
$\left|\begin{array}{ccc}\lambda- 5 & 0 & 4 \\ -12 & \lambda- 1 & 12 \\ -8 & 0 & \lambda- 7\end{array}\right|$$= -(\lambda- 1)\left|\begin{array}{cc} \lambda- 5 & 4 \\ -8 & \lambda+ 7 \end{array}\right|$$= -(\lambda- 1)[(\lambda- 5)(\lambda+ 7)- (-8)(4)]$$=-(\lambda- 1)[(\lambda- 5)(\lambda+ 7)+ 32]$.
The "32" comes from the -8 and 4 in the original matrix.
 
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thank you for helping
I am getting the impression not to many here can help with Linear Algebra
despite all the views of curiosity :cool:I did this with another problem but was kinda :confused: with it

https://www.physicsforums.com/attachments/8909
 
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