2D motion, asking for distant land,

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This discussion focuses on calculating the horizontal launch distance for a model rocket to hit a moving target. The model rocket, weighing 700 grams, is propelled by a constant thrust of 15.0 N and must reach a height of 29 meters. The target moves horizontally at a speed of 15 m/s. The calculated horizontal distance required for the rocket to successfully intercept the target is approximately 33.79 meters.

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Please help

As a science fair project, you want to launch an 700 g model rocket straight up and hit a horizontally moving target as it passes 29 m above the launch point. The rocket engine provides a constant thrust of 15.0 N. The target is approaching at a speed of 15 m/s. At what horizontal distance between the target and the rocket should you launch?
 
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now let us calculate the time of rocket catch 29m.
acceleration: a=(F-mg)/m F=15N ,m=0.7kg, g=10m/s^2
t=sqrt(2s/a)=sqrt[2sm/(F-mg)] s=29m
ok, we got the time, then we calculate the diatance of the target moved in this time.
d=vt=v*sqrt[2sm/(F-mg)] v=15m/s
d=15*sqrt[2*29*0.7/(15-7)]m=33.79m
 

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