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2D motion, asking for distant land,

  1. Jun 11, 2010 #1
    Please help

    As a science fair project, you want to launch an 700 g model rocket straight up and hit a horizontally moving target as it passes 29 m above the launch point. The rocket engine provides a constant thrust of 15.0 N. The target is approaching at a speed of 15 m/s. At what horizontal distance between the target and the rocket should you launch?
     
  2. jcsd
  3. Jun 12, 2010 #2
    now let us calculate the time of rocket catch 29m.
    acceleration: a=(F-mg)/m F=15N ,m=0.7kg, g=10m/s^2
    t=sqrt(2s/a)=sqrt[2sm/(F-mg)] s=29m
    ok, we got the time, then we calculate the diatance of the target moved in this time.
    d=vt=v*sqrt[2sm/(F-mg)] v=15m/s
    d=15*sqrt[2*29*0.7/(15-7)]m=33.79m
     
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