1. The problem statement, all variables and given/known data Member ABD is supported by a pin at A and a pin in a smooth slot at B. Member BC serves as a support post. A 100 N force is applied at D. Determine the reactions at A and B necessary for equilibrium of ABD. 3. The attempt at a solution Ma = 0 = (.5)(Fb) - (1)(83.74) Fb = 167.48 but the answer (for B) is around 190 Newtons. I know I didn't break this question into x and y factors. Could someone explain how to do that, thanks. edit: the angle between the normal of the lever and the 100 N force is 33.13 degrees, resulting in mostly a Y force operating on the end but a small X force as well.