1. The problem statement, all variables and given/known data The coefficient of kinetic friction between the m = 2.6 kg block in Figure P8.35 and the table is 0.28. What is the acceleration of the 2.6 kg block? (The image is attached) ______m/s2 2. Relevant equations Fk= (Mu)(N) 2nd Law statements 3. The attempt at a solution I began by drawing three force diagrams, one for each block. Using the 2.6 and 3 blocks I wrote out 2nd law statements (because the block is shifting right), and substituted in variables for the friction forece equation: Ca= T- Cg Ba= T- Fk Fk=(Mu)(Bg).... (According to my force diagrams , normal force equals weight force) Then I sovled for T on the first equation. Substituting that in for T in the second, and replacing the Fk with the other equation: Ba= Ca+ Cg- (Mu)(Bg) I then solved for a. After plugging in all the numbers, I got a very high number as my a. Near 55, if I recall. What exactly did I do wrong?