3-d harmonic oscillator and SU(3) - how to imagine it?

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SUMMARY

The 3-dimensional harmonic oscillator exhibits SU(3) symmetry due to its spherical symmetry, as established in various academic papers. The eight Gell-Mann generators of SU(3) correspond to the Lie algebra su(3) and act as infinitesimal symmetry transformations of the Hamiltonian, shifting energy among the three linearly independent oscillators while maintaining constant total energy. Key references include D M Fradkin's discussion in the 1964 American Journal of Physics, which clarifies the relationship between angular momentum, the Runge-Lentz tensor, and the eight generators.

PREREQUISITES
  • Understanding of SU(3) symmetry and its generators
  • Familiarity with the concept of Lie algebras
  • Knowledge of the 3-dimensional harmonic oscillator model
  • Basic principles of quantum mechanics and Hamiltonians
NEXT STEPS
  • Study the role of Gell-Mann matrices in SU(3) transformations
  • Explore the relationship between angular momentum and the Runge-Lentz tensor in quantum systems
  • Investigate the holomorphic representation of harmonic oscillators and its implications for SU(N) symmetry
  • Read D M Fradkin's 1964 paper in the American Journal of Physics for deeper insights
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Physicists, quantum mechanics students, and researchers interested in the symmetries of quantum systems, particularly those studying harmonic oscillators and SU(3) symmetry.

franoisbelfor
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The 3-dimensional harmonic oscillator has SU(3) symmetry. This is stated in many papers. It seems to be due to the spherical symmetry of the system. (After all, the idea of a 3d harmonic oscillator is that a mass is attached to the origin with a spring, and that the mass can move in 3 dimensions, with no gravity involved.)

But I have an issue. If this system has SU(3) symmetry, the 8 generators of SU(3) must somehow act on the various eigenstates. How exactly does this happen? Is there a book or a paper on this?

For example, the eight Gell-Mann generators of SU(3) must transform the states of the harmonic oscillator. What do they do? Do they rotate the state? How? Why are there 8 of them?

Thank you for any advice in this matter.

Cheers

François
 
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franoisbelfor said:
But I have an issue. If this system has SU(3) symmetry, the 8 generators of SU(3) must somehow act on the various eigenstates.

The generators are elements of the lie algebra su(3), not the group SU(3). If we take a step away from matrices and imagine the actions of the generators as abstract operators then the generators correspond to infinitesimal symmetry transformations of the Hamiltonian, therefore they do not necessarily transform eigenstates to eigenstates.

For example, the eight Gell-Mann generators of SU(3) must transform the states of the harmonic oscillator.

I just want to point out that the Gell-Mann matrices are one of many equivalent representations for the generators of SU(3).

Why are there 8 of them?

Why 8 generators? Determine the dimension of SU(3), and determine the dimension of the tangent space at the identity, and tell me how many vectors are needed to span this tangent space (the answer is 8).
 
franoisbelfor said:
But I have an issue. If this system has SU(3) symmetry, the 8 generators of SU(3) must somehow act on the various eigenstates. How exactly does this happen? Is there a book or a paper on this?

For example, the eight Gell-Mann generators of SU(3) must transform the states of the harmonic oscillator. What do they do? Do they rotate the state? How? Why are there 8 of them?

Thank you for any advice in this matter.

Cheers

François

D M Fradkin discussed the physics very clearly in the 1964 American Journal of Physics, I found out. The symmetries are the angular momentum and the Runge-Lentz tensor (for the harmonic oscillator in 3d, it is a tensor, not a vector). That makes 3+5=8 generators

The generators shift energy among the 3 linearly independent oscillators, keeping the total energy constant.

François
 
Thanks, François. That's insightful.

In any case, it's easy to see where the SU(N) comes from, but not terribly illuminating. If you work in the holomorphic representation, then the Hamiltonian is H = a^\dagger a which clearly has an SU(N) symmetry. This is also a very elaborate way of determining the degeneracy of such a harmonic oscillator.

Of course, there's the unrelated issue that su(3) contains a bunch of su(2) sub-algebras.
 

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