3 point charges on the vertices of an equilateral triangle

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SUMMARY

The discussion centers on the behavior of forces between point charges positioned at the vertices of an equilateral triangle. When the charges are doubled, the resulting force on each charge increases by a factor of four due to Coulomb's law, expressed as F = k(q1 * q2) / r². The formula demonstrates that if both charges are doubled while maintaining the same distance, the force becomes F = k(2q1 * 2q2) / r², resulting in a quadrupling of the force. This conclusion is derived from the direct relationship between charge magnitude and force in electrostatics.

PREREQUISITES
  • Understanding of Coulomb's law
  • Familiarity with the concept of electric force
  • Knowledge of basic algebra for manipulating equations
  • Concept of point charges and their interactions
NEXT STEPS
  • Study the implications of Coulomb's law in different geometrical configurations
  • Explore the concept of electric fields generated by point charges
  • Learn about superposition principle in electrostatics
  • Investigate the effects of distance on electric force between charges
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Students studying physics, particularly those focusing on electrostatics, as well as educators seeking to explain the principles of electric forces and charge interactions.

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Homework Statement



3 equal point charges on the vertices of a triangle. If the each of the charges are doubled, why is the resulting force on each charge quadrupled?

Homework Equations



F= Fx +Fy

F= kqk2/r^2


The Attempt at a Solution


I got doubled
 
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well the force acting on charged particle (Coulomb's law) is equal to:
[tex]F=k\frac{q_1 q_2}{r^2}[/tex]
if distance is left same, and charges is doubled, you get:
[tex]F=k\frac{2q_1 2q_2}{r^2}=4k\frac{q_1 q_2}{r^2}[/tex]
so the force is bigger four times
 

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