3 point charges on the vertices of an equilateral triangle

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Homework Statement



3 equal point charges on the vertices of a triangle. If the each of the charges are doubled, why is the resulting force on each charge quadrupled?

Homework Equations



F= Fx +Fy

F= kqk2/r^2


The Attempt at a Solution


I got doubled
 
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well the force acting on charged particle (Coulomb's law) is equal to:
[tex]F=k\frac{q_1 q_2}{r^2}[/tex]
if distance is left same, and charges is doubled, you get:
[tex]F=k\frac{2q_1 2q_2}{r^2}=4k\frac{q_1 q_2}{r^2}[/tex]
so the force is bigger four times