3-Qubit Quantum Circuit with 1 CNOT

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SUMMARY

The discussion focuses on generating 8x8 matrices for a 3-qubit quantum circuit involving a CNOT operator. The user seeks an efficient method to create these matrices for any combination of target and controlled qubits without resorting to brute force coding. The recommended solution is to utilize a quantum circuit simulator, which allows for defining qubit operations and simulating the circuit's output to obtain the required matrices directly.

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  • Understanding of quantum circuits and qubit operations
  • Familiarity with the CNOT operator and its role in quantum computing
  • Knowledge of quantum circuit simulators and their functionalities
  • Basic programming skills for implementing simulations
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Quantum computing enthusiasts, researchers, and developers looking to understand and implement quantum circuits, particularly those working with CNOT operations and matrix generation.

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Ok, I have this circuit, and I'm trying to devise a way to create an 8x8 matrix for any given combination of target qubit and controlled qubit.

3Qv6a.png

(I is the identity matrix, and X is the CNOT operator)

I want it to also include the qubit that passes through untouched because I'm trying to write a program that takes a given state of 3 qubits and runs it through the above circuit.

As of now, for any combination of target and control qubit, I've generated the 8x8 matrices on paper, but I wondering if there's an easier way to generate each case?

If I had to, I suppose I could "brute force" code each individual case (i.e. 1 on 2, 1 on 3, 2 on 3 and their opposites), but it seems like I'm missing something quite easy that wouldn't require that...

Thanks in advance.
 
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The easiest way to generate the 8x8 matrices for any combination of target qubit and controlled qubit is to use a quantum circuit simulator. These simulators allow you to define the number of qubits in your circuit, define the desired circuit operations, and simulate the circuit's output. This will give you the exact 8x8 matrix you need for any given combination of target and controlled qubit.
 
Time reversal invariant Hamiltonians must satisfy ##[H,\Theta]=0## where ##\Theta## is time reversal operator. However, in some texts (for example see Many-body Quantum Theory in Condensed Matter Physics an introduction, HENRIK BRUUS and KARSTEN FLENSBERG, Corrected version: 14 January 2016, section 7.1.4) the time reversal invariant condition is introduced as ##H=H^*##. How these two conditions are identical?

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