(3 questions) Reflection and Refraction

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SUMMARY

The discussion focuses on the principles of reflection and refraction, specifically using Snell's Law to solve problems involving light behavior in different mediums. Key examples include calculating the exit angle of light from water and determining angles in a glass prism. The participants emphasize the importance of understanding the index of refraction and applying geometric principles to find angles of incidence and refraction. The discussion highlights the necessity of visual aids, such as ray diagrams, for solving complex refraction problems.

PREREQUISITES
  • Understanding of Snell's Law (ni*sinΘi = nr*sinΘr)
  • Familiarity with the concept of the index of refraction
  • Basic knowledge of geometric principles related to angles
  • Ability to create and interpret ray diagrams
NEXT STEPS
  • Research the index of refraction for various materials
  • Learn how to construct and analyze ray diagrams for refraction
  • Study the geometric properties of prisms and their angles
  • Explore applications of Snell's Law in real-world scenarios
USEFUL FOR

Students studying optics, physics educators, and anyone interested in understanding the behavior of light in different mediums.

whitehorsey
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1. A light source, S, is located 2.0 m below the surface of a swimming
pool and 1.5 m from one edged of the pool. The pool is filled to the
top with water.
a) At what angle does the light reaching the edge of the pool leave the
water?
b) Does this cause the light viewed from this angle to appear deeper or
shallower than it actually is?


2. ni*sinΘi = nr*sinΘr

3. I have no idea how to do this problem.


1. A ray of light is incident upon a 600-600-600 glass prism, n=1.5.
the angle od incidence is 45 degree.
a) Using Snell's law, determine the angle Θr to the nearest degree.
b) Using elementary geometry, determine the values of angles A, B,
and C.
c) Determine angle of refraction.

the picture is an attachment

2. ni*sinΘi = nr*sinΘr

3. a. ni*sinΘi = nr*sinΘr
= sinΘr = nisinΘr/nr
= 1sin60/1.5
= 35.3 degrees

b./c. I have no clue. I know its suppose to be simple geometry but I can't seem to figure it out. :/



1. A sheet of plastic, n = 1.500, 25 mm thick is used in a bank teller's window. A ray of light strikes the sheet at an angle of 45 degrees. The ray leaves the sheet at 45 degrees but at a different location. Use a ray diagram to find the distance between the ray that leaves and the one that would have left in the plastic were not there.

2. ni*sinΘi = nr*sinΘr

3. How would you draw the ray diagram? I don't know if I need to use the 25 mm if so why and how?

Thank YOU! ;)
 

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For 1 draw a picture and use your equation. It's just Snell's Law.

You know the angle from the bottom, the index of refraction of water (look it up if you don't) ... just solve for the angle at exit.

If you can't do that there's no point looking at the other questions.
 

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