MHB 4.1.310 AP calculus Exam Area under to functions

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The discussion revolves around solving the equation where the functions ln(x) and 5-x intersect. The approximate intersection point is found to be x ≈ 3.693, but participants express uncertainty about isolating x. The area between the curves is calculated using integrals, with one participant noting that the problem can be approached using either x or y coordinates. It is clarified that both coordinates of the intersection point are necessary for accurate calculations. The final part of the discussion highlights that part (c) of the problem is a free response question, emphasizing the need for careful consideration in the solution.
karush
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ok I got stuck real soon...

.a find where the functions meet $$\ln x = 5-x$$
e both sides
$$x=e^{5-x}$$ok how do you isolate x?

W|A returned $x \approx 3.69344135896065...$
but not sure how they got itb.?
c.?
 

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FYI, this is a calculator active problem ...

$y = \ln{x} \implies x = e^y$

$y = 5-x \implies x = 5-y$

$$R = \int_0^{1.3065586} (5-y) - e^y \, dy = 2.986$$
 

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so then we don't need to know x of the intersection
 
karush said:
so then we don't need to know x of the intersection

yes, you need both x and y coordinates of the intersection point ...

(a) can be done w/r to x or y ... I went w/r to y because it only requires a single integral expression

(b) requires x ... two integrals

(c) requires y
 
ill go with c
 
karush said:
ill go with c

?

(c) is a free response question, not a choice
 
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