4.1.310 AP calculus Exam Area under to functions

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SUMMARY

The discussion centers on solving the intersection of the functions \( \ln x \) and \( 5 - x \) to find the area between them for the AP Calculus Exam. The intersection point is calculated as \( x \approx 3.693 \) using Wolfram Alpha. The area \( R \) is determined by the integral \( R = \int_0^{1.3065586} (5 - y) - e^y \, dy \), yielding a result of approximately 2.986. The discussion emphasizes the necessity of both x and y coordinates for accurate calculations, with different approaches for parts (a), (b), and (c) of the problem.

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karush
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ok I got stuck real soon...

.a find where the functions meet $$\ln x = 5-x$$
e both sides
$$x=e^{5-x}$$ok how do you isolate x?

W|A returned $x \approx 3.69344135896065...$
but not sure how they got itb.?
c.?
 

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FYI, this is a calculator active problem ...

$y = \ln{x} \implies x = e^y$

$y = 5-x \implies x = 5-y$

$$R = \int_0^{1.3065586} (5-y) - e^y \, dy = 2.986$$
 

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so then we don't need to know x of the intersection
 
karush said:
so then we don't need to know x of the intersection

yes, you need both x and y coordinates of the intersection point ...

(a) can be done w/r to x or y ... I went w/r to y because it only requires a single integral expression

(b) requires x ... two integrals

(c) requires y
 
ill go with c
 
karush said:
ill go with c

?

(c) is a free response question, not a choice
 

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