4.2 Acceleration due to gravity lab error

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Homework Help Overview

The discussion revolves around a lab experiment analyzing the acceleration due to gravity, specifically focusing on the average velocity time graph of a falling mass. Participants are examining discrepancies in the graph, particularly why the best fit line does not start at 0 m/s.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants are questioning the initial conditions of the experiment and the calculation of average velocity. There is discussion about the timing of the mass's fall and how it relates to the average velocity derived from short time intervals.

Discussion Status

The conversation is ongoing, with participants exploring different interpretations of the data and the implications of timing and measurement. Some guidance has been offered regarding the nature of motion during short intervals, but no consensus has been reached.

Contextual Notes

There are indications that the setup of the experiment and the timing method may be influencing the results, but specific constraints or assumptions have not been fully articulated.

jakeginobi

Homework Statement



My best fit-line for my average velocity time graph doesn't seem to start at 0 m/s. I have no idea how to explain this in my conclusion - http://imgur.com/zniGGkw. This lab was conducted by using a recording timer, and a mass. We started the recording timer first, then let go of the mass then stopped the timer once it reached the floor.

Homework Equations


acceleration due to gravity = -9.80 m/s^2

The Attempt at a Solution


I know it couldn't be air resistance in the beginning
 
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I assume the time is for the mass to go from the top to the bottom and that the total it falled was kept the same each time? How did you calculate the average velocity?
 
Each time interval, I selected the average velocity divided 0.050s; for instance at the 7th interval my individual displacement was 0.1689 (m) [downwards], and divided it by 0.050s to find the average velocity
 
It seems you are looking at the motion of the falling object over short time periods, 0.05 s. During such a short time period the object would not be stationary, even at the start. That is it would be approximately 10 x 0.05 = 0.5 m/s
 

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