4 points and distance to middle of square

[th3plan]

I forgot, but how can i get distance to middle of a square let's consider sides are all called A. So do i take a^2+a^2=r^2 and 2a^2=r^2 so r= radical(2)r , but since we want half of that i multiply that by 1/2

This correct ?

 

[HallsofIvy]

I forgot, but how can i get distance to middle of a square let's consider sides are all called A. So do i take a^2+a^2=r^2 and 2a^2=r^2 so r= radical(2)r , but since we want half of that i multiply that by 1/2

This correct ?

It would help if you told us what "a" is! Is it the length of each side? If so then, by the Pythagorean theorem, the diagonal has length $\sqrt{a^2+ a^2}= a\sqrt{2}$. Since the middle of the square is at the center of the diagonal, the distance from any vertex to the middle is $a\sqrt{2}/2$

(Your equation "r= radical(2)r" should be, of course, "r= radical(2)a". I suspect that was a typo.)

 

[tiny-tim]

Hi th3plan!

(have a square-root: √ )

I forgot, but how can i get distance to middle of a square let's consider sides are all called A. So do i take a^2+a^2=r^2 and 2a^2=r^2 so r= radical(2)r , but since we want half of that i multiply that by 1/2

This correct ?

Yup!

and (√2)a/2 = a/√2.