MHB -412.7.3 decide if cosets of H are the same

  • Thread starter Thread starter karush
  • Start date Start date
  • Tags Tags
    Cosets
Click For Summary
The discussion focuses on determining whether specific cosets of the subgroup H, defined as H = {0, ±3, ±6, ±9, ...}, are the same. It establishes that two cosets aH and bH are equal if the difference (b - a) is a member of H. For the cosets 11 + H and 17 + H, as well as -1 + H and 5 + H, they are confirmed to be the same because their differences (6) are multiples of 3. However, the cosets 7 + H and 23 + H are not the same since their difference (16) is not a multiple of 3. The method for checking coset equality is validated through these examples.
karush
Gold Member
MHB
Messages
3,240
Reaction score
5
Let $H=\{0;\pm 3;\pm 6;\pm 9;\cdots\}$.
$\textit{ Use }$
$$aH=bH \textit{ or }aH\cap bH=\oslash$$
$\textit{then..}$
$$aH = bH \textit{ iff } (b-a) \textit{ is in } \textit{H}$$
to decide whether or not the following cosets of H are the same.
$\textsf{a. 11 + H and 17 + H}$
$\textsf{b. -1 + H and 5 + H}$
$\textsf{c. 7 + H and 23 + H}$ok not sure what the official method of this would be but for a. 11+6=17 so the coset would would be just a shift over 6 places. the same shift seens to be true for b and c however the beginning numbers would be different

however the book says that c is no
 
Last edited:
Physics news on Phys.org
karush said:
Let $H=\{0;\pm 3;\pm 6;\pm 9;\cdots\}$.
$\textit{ Use }$
$$aH=bH \textit{ or }aH\cap bH=\oslash$$
$\textit{then..}$
$$aH = bH \textit{ iff } (b-a) \textit{ is in } \textit{H}$$
to decide whether or not the following cosets of H are the same.
$\textsf{a. 11 + H and 17 + H}$
$\textsf{b. -1 + H and 5 + H}$
$\textsf{c. 7 + H and 23 + H}$ok not sure what the official method of this would be but for a. 11+6=17 so the coset would would be just a shift over 6 places. the same shift seens to be true for b and c however the beginning numbers would be different

however the book says that c is no
$H = \{\ldots -9;-6;-3;\ 0;\ 3;\ 6;\ 9 \ldots\}$

For a.: $11+H = \{\ldots 2;\ 5;\ 8;\ 11;\ 14;\ 17;\ 20;\ \ldots\},\quad 17+H = \{\ldots 8;\ 11;\ 14;\ 17;\ 20;\ 23;\ 25 \ldots\}$
Those two sets are the same. The numbers in the list have just been shifted by two places to get from $11+H$ to $17+H$.

For c.: $7+H = \{\ldots -2;\ 1;\ 4;\ 7;\ 10;\ 13;\ 16;\ 19;\ 22;\ 25;\ 28 \ldots\},\quad 23+H = \{\ldots 14;\ 17;\ 20;\ 23;\ 26 \ldots\}$
Those two sets are not the same. The numbers in them do not coincide at all.

Can you see what condition the shifts must satisfy in order for the two cosets to be the same?
 
Yes: your "method" works. 11+ H and 17+ H are the same because 17- 11= 6 is a multiple of 3; -1+ H and 5+ H are the same because 5- (-1)= 6 is a multiple of 3; and 7+ H and 23+ H are NOT the same because 23- 7= 16 is NOT a multiple of 3.
 
I am studying the mathematical formalism behind non-commutative geometry approach to quantum gravity. I was reading about Hopf algebras and their Drinfeld twist with a specific example of the Moyal-Weyl twist defined as F=exp(-iλ/2θ^(μν)∂_μ⊗∂_ν) where λ is a constant parametar and θ antisymmetric constant tensor. {∂_μ} is the basis of the tangent vector space over the underlying spacetime Now, from my understanding the enveloping algebra which appears in the definition of the Hopf algebra...

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
6K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 6 ·
Replies
6
Views
6K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
1K