4x4 matrix that satisfies conditions

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Homework Help Overview

The discussion revolves around constructing a 4x4 matrix based on three different conditions provided by the original poster. The conditions involve mathematical expressions that define the elements of the matrix based on their indices.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants explore the definitions of the indices i and j, with some suggesting to explicitly write out the matrices for each condition. Questions arise regarding which condition the original poster intends to use and the interpretation of the notation in the conditions.

Discussion Status

There is an ongoing exploration of the three conditions, with participants providing their interpretations and examples of the matrices. Some participants express uncertainty about the correctness of the matrices generated and seek clarification on specific entries. Guidance has been offered regarding the notation and the expectations for the matrix entries.

Contextual Notes

Participants note the importance of adhering to the conditions stated and question the clarity of the original poster's intent. There is also mention of the limitations of using the mobile app for posting, which may affect the formatting of questions.

burton95
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A = [aij]

1) aij = i +j
2) aij = i^j-1
3) aij = 1 if |i - j| >1
-1 if |i - j| _< 1

I don't even know where to begin. Are i and j compenents of the matrix? Please help me get started
 
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i and j and indices of the components. I would guess they take the values 1,2,3,4. So 1) would say a11=1+1=2, a12=1+2=3. Etc. Just write out the whole matrix in each case.
 
Mod note: I removed the copied text that Dick refers to, below.[/color]
The three different conditions 1), 2) and 3) describe different matrices. Which one are you doing? And judging by the title, it's supposed to be 4x4.
 
Last edited by a moderator:
Dick said:
The three different conditions 1), 2) and 3) describe different matrices. Which one are you doing? And judging by the title, it's supposed to be 4x4.
Oops, you're right. The first 4x4 should go like...

A_{i,j} =<br /> \begin{pmatrix}<br /> a_{1+1} &amp; a_{1+2} &amp; \cdots &amp; a_{1+j} \\<br /> a_{2+1} &amp; a_{2+2} &amp; \cdots &amp; a_{2+j} \\<br /> \vdots &amp; \vdots &amp; \ddots &amp; \vdots \\<br /> a_{i+1} &amp; a_{i+2} &amp; \cdots &amp; a_{i+j}\\<br /> \end{pmatrix}
 
phion said:
Oops, you're right. The first 4x4 should go like...

A_{i,j} =<br /> \begin{pmatrix}<br /> a_{1+1} &amp; a_{1+2} &amp; \cdots &amp; a_{1+j} \\<br /> a_{2+1} &amp; a_{2+2} &amp; \cdots &amp; a_{2+j} \\<br /> \vdots &amp; \vdots &amp; \ddots &amp; \vdots \\<br /> a_{i+1} &amp; a_{i+2} &amp; \cdots &amp; a_{i+j}\\<br /> \end{pmatrix}

I admire your texing skills but that's pretty strange looking as an answer to the question. The matrix will have numerical entries. And besides, the goal here is not even to give answers. It's to show the poster how to solve it.
 
Dick said:
I admire your texing skills but that's pretty strange looking as an answer to the question. The matrix will have numerical entries. And besides, the goal here is not even to give answers. It's to show the poster how to solve it.
I'm aware how the answer should look, and thank you for the compliment. I'm still trying to learn LaTeX, so I thought this would be an ample opportunity. I am only trying to help. :smile:
 
Thanks. I was trying to come up with one matrix to satisfy all the conditions mentioned. Upon review its states "condition". Wheeewh
 
so I got these as my matrices

1)
2 3 4 5
3 4 5 6
4 5 6 7
5 6 7 8

2)
1 1 1 1
1 2 4 8
1 3 9 27
1 4 16 64

3)
-1 -1 -1 -1
-1 -1 -1 -1
1 -1 -1 -1
1 1 -1 -1

yes, no?
 
burton95 said:
so I got these as my matrices

1)
2 3 4 5
3 4 5 6
4 5 6 7
5 6 7 8

2)
1 1 1 1
1 2 4 8
1 3 9 27
1 4 16 64

3)
-1 -1 -1 -1
-1 -1 -1 -1
1 -1 -1 -1
1 1 -1 -1

yes, no?

The first one looks ok. The second one is ok if the formula is i^(j-1). I'd read i^j-1 as (i^j)-1. For 3) shouldn't there be some ones in the upper right corner too?
 
  • #10
you're correct on the 3rd matrix. The notation for 2) is aij = ij-1. I use the physicsforums.com android app and when I post using the app there is no template. Does this mean that using the app to post questions isn't legitimate? Also is there a way to keep score where I can thank folks for the help?

thanks
 
Last edited:
  • #11
burton95 said:
you're correct on the 3rd matrix. The notation for 2) is aij = ij-1. I use the physicsforums.com android app and when I post using the app there is no template. Does this mean that using the app to post questions isn't legitimate? Also is there a way to keep score where I can thank folks for the help?

thanks

It's odd the android app doesn't give you a template. But posting questions anyway you like is legit. Just show how you attempted to solve it before asking for help. And a simple thanks is fine. And you just did that. You are welcome!
 

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