How to find the determinant of this matrix?

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    Determinant Matrix
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Homework Help Overview

The discussion revolves around finding the determinant of a specific matrix defined by a recursive relationship. Participants are exploring various methods to approach the problem, which falls under linear algebra and matrix theory.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Some participants suggest reducing the matrix to a simpler form, such as a 2x2 matrix, while others propose expressing the matrix as a product of simpler matrices or using polynomial methods. There is also a mention of using row operations to simplify the determinant calculation.

Discussion Status

The discussion is active, with multiple approaches being considered. Participants are sharing ideas and methods without reaching a consensus, indicating a productive exploration of the topic.

Contextual Notes

Participants are navigating the complexities of the determinant calculation and questioning the assumptions behind the matrix's structure and properties. There is an indication of a recursive definition that may influence the determinant's behavior.

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Homework Statement
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I think you all can see that ##a_{(i+1,j+1)} = a_{i,j} + a_{i+1,j} + a_{i,j+1}##

Now the determinant always give me problem. I have and idea to reduce this matrix by Chio to a 2x2 matrix and find the determinant of this 2x2.

Put i was not able to see any pattern to find what how the 2x2 matrix would be (beside symmetric)

Any tips?
 
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I would first try to write the matrix as a product of two simpler matrices, because the construction rule is similar to matrix multiplication. If this would be too complicated, I'd try the polynomial method: ##\det = \sum_{\sigma\in S_n}(-1)^n \ldots##
 
I want to suggest using row operations to reduce the matrix to something more manageable.

What could be helpful is the following.

Adding or subtracting any two rows of a matrix does not change the determinant.
Exchanging two rows of a matrix changes the sign of the determinant.
 
Another idea is to prove by induction that the determinant equals ##2^{(n^2-n)/2}=2^{\binom n 2}##.
 
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