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karush

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ok this is a snip from stewards v8 15.6 ex

hopefully to do all 3 here

$\displaystyle\int_0^1\int_{0}^{1}\int_{0}^{\sqrt{1-x^2}}\dfrac{z}{y+1} \,dxdzdy$

so going from the center out but there is no x in the integrand

$\displaystyle\int_0^{\sqrt{1 - x^2}} \dfrac{z}{y + 1}dx =\dfrac{ \sqrt{1 - x^2} z}{y + 1}$

and

$\displaystyle\int_0^1 \dfrac{ \sqrt{1 - x^2} z}{y + 1} \, dz=\frac{\sqrt{1-x^2}}{2\left(1+y\right)} $

kinda maybe so far?

ok this is a snip from stewards v8 15.6 ex

hopefully to do all 3 here

$\displaystyle\int_0^1\int_{0}^{1}\int_{0}^{\sqrt{1-x^2}}\dfrac{z}{y+1} \,dxdzdy$

so going from the center out but there is no x in the integrand

$\displaystyle\int_0^{\sqrt{1 - x^2}} \dfrac{z}{y + 1}dx =\dfrac{ \sqrt{1 - x^2} z}{y + 1}$

and

$\displaystyle\int_0^1 \dfrac{ \sqrt{1 - x^2} z}{y + 1} \, dz=\frac{\sqrt{1-x^2}}{2\left(1+y\right)} $

kinda maybe so far?

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