5 moles of Hydrogen Iodide dihydrate,

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Discussion Overview

The discussion revolves around the calculation of mass and concentration of Hydrogen Iodide dihydrate, focusing on the molar mass and the implications of including water in the calculations. Participants explore theoretical and practical aspects of working with hydrates in solution.

Discussion Character

  • Technical explanation, Conceptual clarification, Homework-related, Debate/contested

Main Points Raised

  • One participant inquires about the molar mass of Hydrogen Iodide dihydrate and whether to include the mass of the water in the calculation.
  • Another participant confirms that the water must be included in the mass calculation, as it is part of the hydrate.
  • A different participant mentions another example of a hydrate, suggesting that hydrates can be isolated in crystalline form.
  • One participant asks how to determine the number of moles of Hydrogen Iodide dihydrate in a 1 dm³ solution with a concentration of 1 mol/dm³, questioning the feasibility of having a hydrate in solution.
  • Another participant states that the concentration of a solution remains the same regardless of whether the solute is a hydrate or an anhydrous salt, although they acknowledge that there may be specific cases where differences could arise.
  • A participant expresses appreciation for the abbreviation of "mole" to "mol," considering it a time-saving measure.

Areas of Agreement / Disagreement

Participants generally agree on the need to include water in the mass calculation of hydrates, but there is some uncertainty regarding the implications of hydrates in solution and whether they differ from anhydrous salts in practical scenarios.

Contextual Notes

Some participants note that there may be specific cases where the behavior of hydrates in solution could differ from that of anhydrous salts, but these cases are considered rare and not the focus of the current discussion.

DarylMBCP
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If I have 5 moles of Hydrogen Iodide dihydrate, for example, what is the mass? I knw that I have to tke the number of moles times the molar mass to find the mass but what is the molar mass of the compound I suggested? Do I hve to include the extra 2H2O part when finding the molar mass? Thanks for the help.
 
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DarylMBCP said:
If I have 5 moles of Hydrogen Iodide dihydrate, for example, what is the mass? I knw that I have to tke the number of moles times the molar mass to find the mass but what is the molar mass of the compound I suggested? Do I hve to include the extra 2H2O part when finding the molar mass?

Yup. The water's going to be there if you weight it, right?
 


DarylMBCP said:
If I have 5 moles of Hydrogen Iodide dihydrate, for example, what is the mass? I knw that I have to tke the number of moles times the molar mass to find the mass but what is the molar mass of the compound I suggested? Do I hve to include the extra 2H2O part when finding the molar mass? Thanks for the help.

Yes , an example of another hydrate is the hydrate of hydrogen phosphate , it's crystalline which is able to be isolated.
 


Ok, thanks guys. Btw, how do I find the number of moles of Hydrogen Iodide dihydrate in 1dm3 of aqueous solution if the concentration of Hydrogen Iodide dihydrate is 1mol/dm3? Is is even possible to have the concentration of a hydrate in water? Thanks for the help again.
 


If I dissolve 1 mole of substance in 1 liter of solution I have 1M solution. Doesn't matter if it was hydrate, dihydrate or something else. But as solution prepared by dissolving 1 mole of dhydrate is no different from the solution prepared by dissolving 1 mole of anhydrous salt (or 1 mole of decahydrate) - this 'hydrate' part is omitted.

There are probably very specific cases when such solutions will differ - for example it can be impossible to prepare concentrated solution of some substance using hydrated salt (too much water to get correct concentration). But these are rare cases, that can be safely ignored at first approach.
 


Borek do you know who came up with the idea to shorten the word mole to mol?I think it was a brilliant idea and a great time saver. :biggrin:
 


K, thnks for the help guys.
 

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