5-point star resultant force question

In summary, the conversation discusses converting forces into horizontal and vertical components and determining angles in a regular pentagon. The speaker suggests using the uniformity of the star to find the angles and mentions the sum of all angles.
  • #1
jfletch
2
0
Any help on where I start with this question. Need to convert each force into its horizontal and vertical components, but don't know any angles apart from the 70N force acting straight down.
 

Attachments

  • Week 2 Tutorial Questions.pdf
    92.9 KB · Views: 236
Physics news on Phys.org
  • #2
jfletch said:
Any help on where I start with this question. Need to convert each force into its horizontal and vertical components, but don't know any angles apart from the 70N force acting straight down.

The lines of the forces connect the vertices of a regular pentagon to the centre. What angle do they enclose with each other? What are their angles with respect to the positive x axis?

ehild
 

Attachments

  • pentagon.JPG
    pentagon.JPG
    7.7 KB · Views: 407
  • #3
Surely you can figure out the angles. The star is uniform, so the angle is the same between any two adjacent forces. And you know what the sum of all the angles is.
 
  • #4
Thanks for the help.
 
  • #5


To begin solving this question, we can first draw a diagram of the 5-point star and label the forces acting on it. From the given information, we know that there is a 70N force acting straight down. We can also label the other forces as A, B, C, and D.

Next, we need to find the horizontal and vertical components of each force. To do this, we can use trigonometric functions such as sine and cosine. Since we only know the angle of the 70N force, we can use this to find the horizontal and vertical components of that force. The horizontal component would be 70N*cos(0) = 70N and the vertical component would be 70N*sin(0) = 0N.

For the other forces, we can use the Pythagorean theorem to find their magnitudes. For example, for force A, we can use the equation A^2 = (70N)^2 + (70N)^2 to find that A = 99.0N. To find the horizontal and vertical components of A, we can use the angles formed by the force with the horizontal and vertical axes. This can be found by drawing a right triangle with A as the hypotenuse and using the inverse trigonometric functions.

Repeat this process for forces B, C, and D, and you will have the horizontal and vertical components for all the forces acting on the star. Then, to find the resultant force, we can use the vector addition method by adding all the horizontal components together and all the vertical components together. The resultant force would then be the square root of the sum of the squares of the horizontal and vertical components.

In summary, to solve this question, we need to use trigonometric functions, the Pythagorean theorem, and vector addition to find the horizontal and vertical components of each force and then find the resultant force. This process can be applied to other similar problems involving forces acting at different angles.
 

1. What is a 5-point star resultant force?

A 5-point star resultant force is a concept in physics and engineering that represents the combined effect of multiple forces acting on an object. It is typically represented by a 5-point star shape, with each point representing a different force vector and the center representing the overall resultant force.

2. How is a 5-point star resultant force calculated?

The 5-point star resultant force is calculated by adding together all of the individual force vectors that are acting on an object. This can be done either mathematically, using vector addition, or graphically, by drawing the force vectors to scale and measuring the resulting resultant force vector.

3. What factors affect the magnitude and direction of a 5-point star resultant force?

The magnitude and direction of a 5-point star resultant force are affected by the individual magnitudes and directions of the forces acting on the object. Additionally, the angle between the forces and the object, as well as the position of the forces relative to each other, can also impact the resultant force.

4. How is a 5-point star resultant force used in real-world applications?

The concept of a 5-point star resultant force is used in a variety of real-world applications, including structural engineering, aerospace engineering, and mechanical engineering. It is also used in physics experiments to study the effects of multiple forces on an object.

5. How can understanding 5-point star resultant force help solve real-world problems?

Understanding the concept of a 5-point star resultant force is crucial for solving real-world problems involving multiple forces. By accurately calculating the resultant force, engineers and scientists can design structures and machines that can withstand and efficiently utilize the forces acting on them.

Similar threads

  • Introductory Physics Homework Help
Replies
11
Views
226
  • Introductory Physics Homework Help
Replies
10
Views
1K
  • Introductory Physics Homework Help
Replies
8
Views
235
  • Introductory Physics Homework Help
Replies
5
Views
743
  • Introductory Physics Homework Help
Replies
5
Views
2K
  • Introductory Physics Homework Help
Replies
30
Views
1K
  • Introductory Physics Homework Help
Replies
3
Views
925
  • Introductory Physics Homework Help
Replies
9
Views
725
  • Introductory Physics Homework Help
Replies
4
Views
1K
  • Introductory Physics Homework Help
Replies
2
Views
1K
Back
Top