MHB 639.7.6.97 write an equivalent polar equation

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The discussion focuses on converting the Cartesian equation x² + (y - 1)² = 1 into its equivalent polar form. Initially, the equation is expanded and rearranged to x² + y² = 2y. Substituting r² for x² + y² and r cos(θ) for y leads to the equation r² = 2r sin(θ). The final polar equation is presented as r = 2 sin(θ). The conversion process highlights the importance of correctly substituting variables in polar coordinates.
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$\textrm{write an equivalent polar equation}$
\begin{align*}\displaystyle
x^2+(y-1)^2&=1
\end{align*}
$\textrm{expand and rearrange}$
$$x^2+y^2=2y$$
$\textrm{substitute $r^2$ for $x^2+y^2$
and $r \cos(\theta)$ for $y$}$
$\textrm{then}$
$$r^2=2r\cos(\theta)$$
$\textrm{or}$
$$r=2 \cos(\theta)$$

kinda maybe
 
Last edited:
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Looks good to me. (Yes)

edit: On second thought...there is an issue...$2y=2r\sin(\theta)$...:D
 
got it.

should of seen that:cool:

- - - Updated - - -

$\textrm{write an equivalent polar equation}$
\begin{align*}\displaystyle
x^2+(y-1)^2&=1
\end{align*}
$\textrm{expand and rearrange}$
$$x^2+y^2=2y$$
$\textrm{substitute $r^2$ for $x^2+y^2$
and $r \cos(\theta)$ for $y$}$
$\textrm{then}$
$$r^2=2r\sin(\theta)$$
$\textrm{or}$
$$r=2 \sin(\theta)$$
 
I have been insisting to my statistics students that for probabilities, the rule is the number of significant figures is the number of digits past the leading zeros or leading nines. For example to give 4 significant figures for a probability: 0.000001234 and 0.99999991234 are the correct number of decimal places. That way the complementary probability can also be given to the same significant figures ( 0.999998766 and 0.00000008766 respectively). More generally if you have a value that...

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