MHB 639.7.6.97 write an equivalent polar equation

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    Equivalent Polar
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The discussion focuses on converting the Cartesian equation x² + (y - 1)² = 1 into its equivalent polar form. Initially, the equation is expanded and rearranged to x² + y² = 2y. Substituting r² for x² + y² and r cos(θ) for y leads to the equation r² = 2r sin(θ). The final polar equation is presented as r = 2 sin(θ). The conversion process highlights the importance of correctly substituting variables in polar coordinates.
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$\textrm{write an equivalent polar equation}$
\begin{align*}\displaystyle
x^2+(y-1)^2&=1
\end{align*}
$\textrm{expand and rearrange}$
$$x^2+y^2=2y$$
$\textrm{substitute $r^2$ for $x^2+y^2$
and $r \cos(\theta)$ for $y$}$
$\textrm{then}$
$$r^2=2r\cos(\theta)$$
$\textrm{or}$
$$r=2 \cos(\theta)$$

kinda maybe
 
Last edited:
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Looks good to me. (Yes)

edit: On second thought...there is an issue...$2y=2r\sin(\theta)$...:D
 
got it.

should of seen that:cool:

- - - Updated - - -

$\textrm{write an equivalent polar equation}$
\begin{align*}\displaystyle
x^2+(y-1)^2&=1
\end{align*}
$\textrm{expand and rearrange}$
$$x^2+y^2=2y$$
$\textrm{substitute $r^2$ for $x^2+y^2$
and $r \cos(\theta)$ for $y$}$
$\textrm{then}$
$$r^2=2r\sin(\theta)$$
$\textrm{or}$
$$r=2 \sin(\theta)$$
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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