# 8*pi in the Einstein field equations?

1. Sep 15, 2013

### pellman

A typical formulation of the Einstein equations is

$$R_{\mu\nu}-\frac{1}{2}Rg_{\mu\nu}+\Lambda g_{\mu\nu}=\frac{8\pi G}{c^4}T_{\mu\nu}$$

The $\frac{G}{c^4}$ make the units work out. What about the 8*pi? Why is this necessary?

2. Sep 15, 2013

### WannabeNewton

The field equations have to agree with Newtonian gravity in the Newtonian limit.

Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook