- #1

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[tex]R_{\mu\nu}-\frac{1}{2}Rg_{\mu\nu}+\Lambda g_{\mu\nu}=\frac{8\pi G}{c^4}T_{\mu\nu}[/tex]

The [itex]\frac{G}{c^4}[/itex] make the units work out. What about the 8*pi? Why is this necessary?

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- Thread starter pellman
- Start date

- #1

- 675

- 4

[tex]R_{\mu\nu}-\frac{1}{2}Rg_{\mu\nu}+\Lambda g_{\mu\nu}=\frac{8\pi G}{c^4}T_{\mu\nu}[/tex]

The [itex]\frac{G}{c^4}[/itex] make the units work out. What about the 8*pi? Why is this necessary?

- #2

WannabeNewton

Science Advisor

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The field equations have to agree with Newtonian gravity in the Newtonian limit.

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