8*pi in the Einstein field equations?

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
1 replies · 4K views
pellman
Messages
683
Reaction score
6
A typical formulation of the Einstein equations is

[tex]R_{\mu\nu}-\frac{1}{2}Rg_{\mu\nu}+\Lambda g_{\mu\nu}=\frac{8\pi G}{c^4}T_{\mu\nu}[/tex]

The [itex]\frac{G}{c^4}[/itex] make the units work out. What about the 8*pi? Why is this necessary?
 
on Phys.org