What is the potential difference between points a and b?

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SUMMARY

The discussion centers on calculating the potential difference between points a and b in a 1000-turn loop of wire with a radius of 0.037m connected to a 20 Ohm resistor, subjected to a time-varying magnetic field described by B=gt, where g=0.25 T/s. The relevant equation for electromotive force (EMF) is E = -NA(dB/dt). Participants clarify that dB/dt can be derived from the given B=gt, leading to dB/dt = 0.25 T/s. The potential difference can thus be calculated using these values.

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Homework Statement


A 1000-turn loop (radius = 0.037m) of wire is connected to a (20 Ohm) resistor as shown in the figure. A magnetic field is directed perpendicular to the plane of the loop. The field points into the paper and has a magnitude that varies in time as B=gt, where g=0.25 T/s. Neglect the resistance of the wire.
http://capa-new.colorado.edu/msuphysicslib/Graphics/Gtype64/prob03a_cj22.26.gif

What is the magnitude of the potential difference between points a and b?



Homework Equations



equation is E = -NA ((dB(t))/dt) but how do u find what t and what is B(t)?

The Attempt at a Solution


cant attempt cause i don't know what t and B(t) are

PLEASE HELP!
 
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You were give B=gt. You have the value of 'g'. I think you can easily find dB/dt.
 
ok well i don't remember how to find B with what is given to me. sorry. if you can just give me some equations i can do the work. not asking for u to do the work for me
 
shimizua said:
ok well i don't remember how to find B with what is given to me. sorry. if you can just give me some equations i can do the work. not asking for u to do the work for me



shimizua said:
The field points into the paper and has a magnitude that varies in time as B=gt, where g=0.25 T/s.


B=gt...dB/dt :confused:

B=0.25t...dB/dt = ?


B=t2,dB/dt = 2t
 
Last edited:

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