A 2.0-kg ball is travelling east at 8.0 ~ Momentum

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SUMMARY

The discussion centers on a perfectly elastic collision involving a 2.0-kg ball traveling east at 8.0 m/s and a 3.0-kg ball traveling west at 10.0 m/s. The conservation of momentum and kinetic energy principles are applied to determine the final velocities of both balls post-collision. The momentum equation M1Vi + M2Vi = M1Vf + M2Vf and the kinetic energy equation 1/2(M1)(Vi)^2 + 1/2(M2)(Vi)^2 = 1/2(M1)(Vf)^2 + 1/2(M2)(Vf)^2 are crucial for solving this problem.

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A 2.0-kg ball is traveling east at 8.0 m/s when it has a perfectly elastic head-on collision with a 3.0-kg ball traveling west at 10.0 m/s. What are the final velocities of the two balls?

Please help I don't know where to start
 
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You know momentum is conserved when bodies collide, start with the momentum principle:
M1Vi + M2Vi = M1Vf + M2Vf

And try another formula, which represents the conservation of kinetic energy:

1/2(M1)(Vi)^2 + 1/2(M2)(Vi)^2 = 1/2(M1)(Vf)^2 + 1/2(M2)(Vf)^2
 

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