If you are standing on the earth and you drop a ball, the ball falls to the ground due to the force of gravity acting on it.(adsbygoogle = window.adsbygoogle || []).push({});

Now imagine you are in an upward accelerating elevator in space. You let go of a ball that you are holding in your hand. The ball Is stationary in space, but the elevator floor is accelerating upward and hits the ball. This means that relative to an observer standing on the floor of the elevator, the ball appears to fall to the ground. The ball falls in the exact same way as it does when you are standing on the earth.

According to the principle of equivalence, no experiment from inside the elevator can tell whether the ball is falling or whether the elevator is accelerating upward. Therefore, the experience inside an upward accelerating elevator is indistinguishable from the experience of standing on the earth in the earth's gravity.

What's strange here is that no force is acting on the ball in the elevator causing it to fall. However, when standing on the earth, the earth's gravity IS acting on the ball causing it to fall.

So, how can a ball fall inside an elevator WITH NO FORCE ACTING ON THE BALL? How is this possible?

In one situation (standing on the earth), A FORCE is acting on the ball. In the other situation, NO FORCE is acting on the ball. So even though one situation has a force acting on the ball (standing on the earth), and the other situation has no force acting on the ball (elevator), both situations are an identical experience where the ball falls to the ground. How is this possible?

**Physics Forums - The Fusion of Science and Community**

# A ball falls with no force acting on it

Know someone interested in this topic? Share a link to this question via email,
Google+,
Twitter, or
Facebook

- Similar discussions for: A ball falls with no force acting on it

Loading...

**Physics Forums - The Fusion of Science and Community**