A ball is thrown straight up from ground level, reaching a height of 136.1 meters after 6.1 seconds, with an acceleration due to gravity of 9.8 m/s². To find the initial speed (Vi), the kinematic equation used is Δx = Vi * t + 1/2 * a * t². Substituting the known values into the equation allows for the calculation of Vi, which is essential for solving the problem accurately.
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Delta x= 136.1Emely said:A ball is thrown straight up from ground level. After a time 6.1 s, it passes a height of 136.1 m. What was its initial speed? The accelera-
tion due to gravity is 9.8 m/s2 . Answer in units of m/s.
Homework Equations
The Attempt at a Solution
I did itCWatters said:Please show your attempt at the problem (forum rules).
Emely said:Delta x= 136.1
T=6.1
A=9.8
Vi*t+1/2at^2