A baseball is thrown straight up with initial speed

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SUMMARY

A baseball thrown straight up with initial speed v(o) experiences a reduction in speed upon returning to its initial height due to the work done against air resistance. The energy lost to air resistance results in a lower kinetic energy at the point of return compared to the initial kinetic energy. Additionally, when considering projectiles at different angles, the maximum height achieved varies because the vertical component of velocity is affected by the angle of projection, while air resistance further complicates the energy dynamics during ascent and descent.

PREREQUISITES
  • Understanding of basic physics concepts such as kinetic energy and potential energy.
  • Familiarity with projectile motion principles.
  • Knowledge of air resistance and its effects on motion.
  • Basic algebra for calculating energy and velocity components.
NEXT STEPS
  • Study the principles of energy conservation in the presence of non-conservative forces.
  • Learn about the effects of air resistance on projectile motion.
  • Explore the equations of motion for projectiles at various angles.
  • Investigate real-world applications of projectile motion in sports and engineering.
USEFUL FOR

Students of physics, educators teaching mechanics, and anyone interested in understanding the dynamics of projectile motion and the impact of air resistance.

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A baseball is thrown straight up with initial speed v(o). If air resistance cannot be ignored, when the ball returns to its initial height its speed is less than v(o). Explain why, using energy concepts.
I am very confused as to why this is.

A projectile has the same initial kinetic energy no matter what the angle of projection. Why doesn't it rise to the same maximum height in each case?

Is it because the velocity in the x-direction is different?
 
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If air resistance cannot be ignored,

What happens when the ball travels through the air?¨
Also, if the ball is thrown straight up the x-coordidate will not change.
 

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