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A block of mass m = 1.6 kg is dropped from height h = 61 cm (height above the spring, not total height) onto a spring of spring constant k = 1820 N/m (Fig. 8-38). Find the maximum distance the spring is compressed.

2. Relevant equations

K=-U, since all energy is conserved, work would equal zero.

3. The attempt at a solution

basically kinetic energy is zero, since its starts from zero and ends with zero.

so i this means that the potential energy must equate.

mgh (potential energy from block at H) = (kx^2)/2(potential energy from spring)

so basically the height from the spring is disclosed, but the spring compression isnt.

I tried this first

mg(x+h)=1/2kx^2

1.6kg * 9.8 m/s^2(x+.61cm)=910n/m *x^2

but it gives me an awkward quadratic equation, where the number under the square root would be negative.

I also tried to find to find the kinetic energy right before it touches the spring, and then apply it to the conservation of energy, where 1/2mvf^2=1/2kx^2 but that ddidnt work either, any suggestions?

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# Homework Help: A block dropped on a spring, distance compressed unknown.

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