1. A block of mass m = 1.6 kg is dropped from height h = 61 cm (height above the spring, not total height) onto a spring of spring constant k = 1820 N/m (Fig. 8-38). Find the maximum distance the spring is compressed. 2. Relevant equations K=-U, since all energy is conserved, work would equal zero. 3. The attempt at a solution basically kinetic energy is zero, since its starts from zero and ends with zero. so i this means that the potential energy must equate. mgh (potential energy from block at H) = (kx^2)/2(potential energy from spring) so basically the height from the spring is disclosed, but the spring compression isnt. I tried this first mg(x+h)=1/2kx^2 1.6kg * 9.8 m/s^2(x+.61cm)=910n/m *x^2 but it gives me an awkward quadratic equation, where the number under the square root would be negative. I also tried to find to find the kinetic energy right before it touches the spring, and then apply it to the conservation of energy, where 1/2mvf^2=1/2kx^2 but that ddidnt work either, any suggestions?