A block of mass m=0.2 kg, is pushed by a spring of stiffness k=300 N/m

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Homework Help Overview

The problem involves a block of mass 0.2 kg being pushed by a spring with a stiffness of 300 N/m, initially compressed by 10 cm, moving up a wedge inclined at 30°. The friction coefficient between the block and the wedge is 0.6. Participants are exploring how far the block will travel along the wedge before stopping.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss various formulas related to oscillation and energy, questioning the appropriateness of using simple harmonic motion (SHM) in this context. There are attempts to calculate angular frequency and period, but doubts are raised about the relevance of these calculations. Some participants suggest considering energy approaches, while others express uncertainty about the initial conditions and setup of the problem.

Discussion Status

The discussion is ongoing, with participants sharing different interpretations of the problem setup and exploring energy considerations. Some guidance has been offered regarding the potential energy of the spring and the energy lost to friction, but no consensus has been reached on the correct approach or solution.

Contextual Notes

Participants note the lack of a diagram and the ambiguity regarding whether the block is attached to the spring or not, as well as the starting position of the block. These factors contribute to the complexity of the problem.

selhai97
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I am currently taking a physics class and I'm studying for the final and I've been stuck on this problem and haven't been able to find help from the book nor help from online.

The professor said the answer was .56m, but I've been trying formulas for about an hour now and haven't been getting anything close to that.

Help please?


1. Homework Statement


A block of mass m=0.2 kg, is pushed by a spring of stiffness k=300 N/m, initially compressed by A=10cm, up the 30° wedge. If the friction coefficient between the block and the wedge is 0.6, how far will the block pass in m along the wedge before it stops?

Homework Equations



I think:
ω = √(k/m)
T = (2π)/ω
x = Acos(ωt + φ)

The Attempt at a Solution


[/B]
ω = √(300/.2) = 7.7
T = (2π)/7.7 = .82
x = (10)cos(7.7*.82) = 9.99

Like I said, I've been trying different formulas for about an hour now, so I don't think I'm using the right ones.

Any help would be amazing, thank you!
 
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selhai97 said:
I am currently taking a physics class and I'm studying for the final and I've been stuck on this problem and haven't been able to find help from the book nor help from online.

The professor said the answer was .56m, but I've been trying formulas for about an hour now and haven't been getting anything close to that.

Help please?


1. Homework Statement


A block of mass m=0.2 kg, is pushed by a spring of stiffness k=300 N/m, initially compressed by A=10cm, up the 30° wedge. If the friction coefficient between the block and the wedge is 0.6, how far will the block pass in m along the wedge before it stops?

Homework Equations



I think:
ω = √(k/m)
T = (2π)/ω
x = Acos(ωt + φ)

The Attempt at a Solution


[/B]
ω = √(300/.2) = 7.7
T = (2π)/7.7 = .82
x = (10)cos(7.7*.82) = 9.99

Like I said, I've been trying different formulas for about an hour now, so I don't think I'm using the right ones.

Any help would be amazing, thank you!

The problem involves a wedge at an angle, gravity, a spring and friction? I'm not sure it's a good idea to use SHM, which would be about the frequency of oscillations of the system.
 
PS You might want to check those numbers. Do you have a diagram?
 
PeroK said:
PS You might want to check those numbers. Do you have a diagram?

No, no diagram, that's all the information that I was given.
 
selhai97 said:
No, no diagram, that's all the information that I was given.

The difficulty as I see it is that on a ##30°## angle, a coefficient of friction of ##0.6## more than cancels gravity. In any case, the nett force is low. With those numbers, it's effectively just the spring, with a small variation due to the slope.

Without the slope, it should move ##20cm##.

Also, even if you take friction out of the equation, the PE of the mass is low compared to the spring. Even a mass hanging on that spring wouldn't stretch it much. You could work that out.

I'd leave it. It doesn't look right to me.
 
PeroK said:
The difficulty as I see it is that on a ##30°## angle, a coefficient of friction of ##0.6## more than cancels gravity. In any case, the nett force is low. With those numbers, it's effectively just the spring, with a small variation due to the slope.

Without the slope, it should move ##20cm##.

Also, even if you take friction out of the equation, the PE of the mass is low compared to the spring. Even a mass hanging on that spring wouldn't stretch it much. You could work that out.

I'd leave it. It doesn't look right to me.

Alright, well thanks anyways! I really appreciate it.
 
The problem doesn't specify if the block is attached to the spring or whether it is unattached, or what is to be considered the block's starting position (before the spring compression or after?).

Either way I'd suggest an energy approach.
 
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gneill said:
The problem doesn't specify if the block is attached to the spring or whether it is unattached, or what is to be considered the block's starting position (before the spring compression or after?).

Either way I'd suggest an energy approach.

Yes, of course, if the mass was pushed down on the spring and not attached to it!
 
gneill said:
The problem doesn't specify if the block is attached to the spring or whether it is unattached, or what is to be considered the block's starting position (before the spring compression or after?).

Either way I'd suggest an energy approach.

You wouldn't use something like this right?
max = -mgsinθ
vxf2 = vxi2 + 2aΔx
 
  • #10
selhai97 said:
You wouldn't use something like this right?
max = -mgsinθ
vxf2 = vxi2 + 2aΔx
Nope. I'd deal directly with the energies (kinetic and potential). The only tricky bit is handling the spring action since the block and spring become disengaged at some point.
 
  • #11
gneill said:
Nope. I'd deal directly with the energies (kinetic and potential). The only tricky bit is handling the spring action since the block and spring become disengaged at some point.

So PE = mgh and KE = (½)mv2?

Are there other equations that involve the A and k and μ?

I'm sorry if I'm so lost, physics is my hardest subject.
 
  • #12
selhai97 said:
So PE = mgh and KE = (½)mv2?

Are there other equations that involve the A and k and μ?

I'm sorry if I'm so lost, physics is my hardest subject.
Look into formulas pertaining to the potential energy stored by a spring and the energy lost to friction.
 

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