A closed organ pipe has a length of 2.40 m?

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A closed organ pipe with a length of 2.40 m produces a frequency of 35.7 Hz based on the speed of sound at 343 m/s. When a second pipe is played, a beat frequency of 1.40 Hz indicates that the second pipe is too long by 0.10 m. The discussion emphasizes the need for relevant equations and methods to solve the problems presented. Participants encourage sharing any attempted solutions to facilitate assistance. Clear guidance on how to approach the problem is sought, particularly for part b.
TheCuriosity
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A closed organ pipe has a length of 2.40 m.

a.) What is the frequency of the note played by the pipe? Use
343 m/s as the speed of sound.

b.) When a second pipe is played at the same time, a 1.40 Hz beat note is heard.
By how much is the second pipe too long?

The a.) problem's solution is 35.7 Hz. and b.) problem's solution is 0.10 m

The actual problem here is that I don't know how to properly solve b.)
 
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Please show some work.
- What are the relevant equations for this problem?
- What have you done to try to solve the problem?
 
Curiosity,there's a template provided.Use that and you won't get into any trouble
 
I'm lost... I'm new here.I just don't know here to post my question lol. I wasn't trying to solve this problem. Can you guys help me and tell me how to solve both of a.) and b.)and tell me where can I post this question if this was the wrong section.Thanks in advanced :)
 
I just read Mentor's message. I'm sorry for messing up xDI understand that you guys won't do my homework, but could you PLEASE help me and explain how to solve b.) ?
 
TheCuriosity said:
I understand that you guys won't do my homework, but could you PLEASE help me and explain how to solve b.) ?
This is the correct section.So as the Mentor said,
- What are the relevant equations for this problem?
- What have you done to try to solve the problem?

Only then will we be able to help you.Sorry :frown:
If that was a question given to you,you must be knowing some relevant equations or some method to solve it.
 
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