# I A computational model of Bell correlations

1. Dec 17, 2017

### jk22

Trying to reproduce the correlation we could try the following reasoning :

The model is : $$C(a,b)=\int \underbrace{A(a,x)\cdot B(b,x)}_{AB(a,b,x)}dx$$
more generally :

$$AB(a,b,x)=g(A(a,x),B(b,x))$$

numerically an exhaustive search over the functions : $$g,A,B : \{0,1\}^2->\{0,1\}$$ since a,b can take 2 values and x too for the spin 1/2 case (we could remap the names of the two angles)

The total number of functions AB is $$2^{(2^3)}=256$$

The decomposition above gave 192 functions generated.

Hence i came to the paradox : even if in this way 75% of the functions can be generated , the quantum real function shall be in the remaining.

But then this also lead to the fact that the decomposition $$AB(a,b,x)=g(h(A(a,x),B(b,x)),A'(a,x))$$
Gives 256 over 256 functions (but seems physically akward or unacceptable)?

I would like to try functions thst can take 3 values but on my pc it will last weeks...

Last edited: Dec 17, 2017
2. Apr 14, 2018

### jk22

In fact nonlocality is hidden here, since if the angles can take $$na,nb$$ values then the cube can be sliced in $$nb$$ functions of $$a$$ and $$\lambda$$, hence it depends on $$a$$ and a property of b.