A cylinder, with a rope wrapped around it, is placed on top of an inclined plane.If the speed of the cylinder in the bottom of the plane, when the angle of the plane is 30 degrees, is 1m/s, find what speed will the cylinder have when it is placed on a plane with an angle of 60 degrees. The length of the plane is 3m, radius of the cilinder is 0,5m, and the coefficient of friction is 0.2. Find the time needed for the cylinder to get to the bottom of the plane in case of a 60 degrees angle and find angular velocity of the cylinder when it is exactly on half of the height of the plane.
I hope I translated this correctly and that you'll be able to get it. Any help appreciated.
picture: http://img822.imageshack.us/img822/3240/screenshot3wb.png [Broken]
I dont know how to put the equations right. Both friction and tension are needed in translational part. I thought of something like this:
mgsin[tex]\beta[/tex] - T - Fr = ma
for the rotational part:
M = Mt - Mfr
I dont know what to do next.
The Attempt at a Solution
I tried something using conservation of energy to find speed at the bottom of the plane, but I dont think I got it right cause I never used the coefficient of friction in my calculations nor tension of the rope.
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