Is (x + a + b)^7 - x^7 - a^7 - b^7 Divisible by x^2 + (a + b)x + ab?

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The problem of determining if (x + a + b)^7 - x^7 - a^7 - b^7 is divisible by x^2 + (a + b)x + ab is approached by recognizing that the factors of the divisor are (x + a) and (x + b). To prove divisibility, it is necessary to show that the expression is divisible by both factors. A suggested method involves rewriting terms and simplifying the expression. While the task may seem daunting due to the complexity of expanding a trinomial to the seventh power, it is emphasized that a systematic approach can yield results. Ultimately, the problem is solvable with careful manipulation of the algebraic expressions involved.
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My maths teacher says this problem is not as impossible as it seems, but I just can't solve it.

Show that (x + a + b)^7 - x^7 - a^7 - b^7 is divisble by
x^2 + (a + b)x +ab.
 
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Looking for the easy way out huh ?
You can always solve the entire excercise...

Live long and prosper.
 
Show that (x + a + b)^7 - x^7 - a^7 - b^7 is divisble by x^2 + (a + b)x +ab.

Hint:
Notice that (x+a) and (x+b) are the 2 factors of x^2 + (a + b)x +ab.
So it is equivalent to show that (x + a + b)^7 - x^7 - a^7 - b^7 is divisible by both (x+a) and (x+b).

Let f(x) = (x + a + b)^7 - x^7 - a^7 - b^7
...
...
...
...


Can you continue from here?

Hope this help. :smile:
 
just write everything out
eg. (x+a)^2=x^2+2xa+a^2

maybe rewrite some terms then and you will see that it is divisible by x^2 + (a + b)x +ab
 
KL has the easy way!

Writing it out however... *shudder* I wouldn't wish writing out a trinomial to the 7th power to anyone!

Hurkyl
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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