A function composition problem

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The problem involves finding the composition of functions g(f(x)) where f(x) is defined as f(x) = sin^2x + sin^2(x + π/3) + cosxcos(x + π/3). The key point is that g(5/4) = 1, leading to the conclusion that g(f(x)) must equal 1 when f(x) simplifies to 5/4. Simplifying f(x) using trigonometric identities reveals that it indeed simplifies to 5/4, confirming that g(f(x)) equals 1. The discussion emphasizes the importance of careful simplification and application of common sense in solving the problem.
Raghav Gupta
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Homework Statement


If ## f(x) = sin^2x + sin^2(x+ π/3) + cosxcos(x+ π/3) ## and $$g(5/4)=1$$, then ##(gof)(x)## is equal to?
Options are
0
1
sinx
None of these

Homework Equations


I know gof(x) is g(f(x)) but here g(x) is not given.

The Attempt at a Solution


Basically I think we have to put f(x) value in g(x) but here g(x) is not given,
What's the use of g(5/4) ?
 
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Raghav Gupta said:

Homework Statement


If ## f(x) = sin^2x + sin^2(x+ π/3) + cosxcos(x+ π/3) ## and $$g(5/4)=1$$, then ##(gof)(x)## is equal to?
Options are
0
1
sinx
None of these

Homework Equations


I know gof(x) is g(f(x)) but here g(x) is not given.

The Attempt at a Solution


Basically I think we have to put f(x) value in g(x) but here g(x) is not given,
What's the use of g(5/4) ?
Use trig sum formulas to simplify ## f(x) = sin^2x + sin^2(x+ π/3) + cosxcos(x+ π/3) ##. If you're careful, you can get this simplfied a great deal.
 
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Mark44 said:
Use trig sum formulas to simplify ## f(x) = sin^2x + sin^2(x+ π/3) + cosxcos(x+ π/3) ##. If you're careful, you can get this simplfied a great deal.
By simplifying I got,
## 5/4 + \frac{√3}{2}sin2x ##.
 
Sorry, carefulness was required as you said.
Got on simplifying now 5/4, and then the answer is 1.
Thanks for the motivation of simplifying.
 
Raghav Gupta said:
Sorry, carefulness was required as you said.
Got on simplifying now 5/4, and then the answer is 1.
Thanks for the motivation of simplifying.
Yes, that's what I got as well.
 
Since the only g value you were given was "5/4", if this problem had an answer it had to be 5/4! Of course, you needed Mark44's suggestion to show that it had a solution.
 
Ya sometimes applying common sense is of great use but I was thinking something else.
 

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