A Hamiltonian represented by a matrix, find the eigevalues

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SUMMARY

The discussion focuses on finding the eigenvalues and eigenstates of a Hamiltonian represented by the matrix H = [[3, 0, -1], [0, a, 0], [-1, 0, 3]]. The eigenstate (1/√2)(1, 0, 1) corresponds to an eigenvalue of 2 eV. Participants suggest using the determinant of the modified matrix (H - E) to derive the remaining eigenstates and their associated eigenenergies. The process involves diagonalizing the matrix and applying linear algebra techniques to solve for the eigenstates.

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Jdraper
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Homework Statement


Been struggling with a particular problem that keeps coming up in one of my modules, so i thought i'd see if anyone here can enlighten me.

A Hamiltonian H0 is represented by the matrix:

top row: 3 0 -1
Middle row: 0 a 0
Bottom row: -1 0 3

(Unsure how to display matrices)

where is a dimensionless parameter. Show that (1/√2)(1 0 1) is an
eigenstate of the Hamiltonian and derive its eigenvalue. Find the other
two eigenstates and the associated eigenenergies.

Homework Equations


n/a

The Attempt at a Solution



Can find the eigenenergy associated with the eigenstate given to us with relative ease, it has a value of 2eV.

However finding the remaining eigenstates has always puzzled me. Is there easy way to find them? as opposed to learning how to use row operators.

Thanks, John
 
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I'll try contribute something, it could be wrong but might give you some ideas. for

H =<br /> \begin{pmatrix}<br /> 3 &amp; 0 &amp; -1\\<br /> 0 &amp; a &amp; 0\\<br /> -1 &amp; 0 &amp; 3<br /> \end{pmatrix}

we can write

\begin{pmatrix}<br /> 3 &amp; 0 &amp; -1\\<br /> 0 &amp; a &amp; 0\\<br /> -1 &amp; 0 &amp; 3<br /> \end{pmatrix} \Psi = E\Psi

we can introduce the identity operator

\begin{pmatrix}<br /> 3 &amp; 0 &amp; -1\\<br /> 0 &amp; a &amp; 0\\<br /> -1 &amp; 0 &amp; 3<br /> \end{pmatrix} \Psi =<br /> \begin{pmatrix}<br /> 1 &amp; 0 &amp; 0\\<br /> 0 &amp; 1 &amp; 0\\<br /> 0 &amp; 0 &amp; 1<br /> \end{pmatrix}<br /> E\Psi

put E in the matrix and minus from the left hand side so

\begin{pmatrix}<br /> 3-E &amp; 0 &amp; -1-E\\<br /> 0 &amp; a-E &amp; 0\\<br /> -1-E &amp; 0 &amp; 3-E<br /> \end{pmatrix} \Psi = 0

we can then insert the matrix form of the eigen state

\begin{pmatrix}<br /> 3-E &amp; 0 &amp; -1-E\\<br /> 0 &amp; a-E &amp; 0\\<br /> -1-E &amp; 0 &amp; 3-E<br /> \end{pmatrix}<br /> \begin{pmatrix}<br /> a_{1}\\ a_{2}<br /> \\ a_{3}<br /> <br /> \end{pmatrix}<br /> = 0

then take the determinant and this will give you the possible energy values. for each energy value put it back into the matrix and it will tell you what a1, a2 and a3 are in relation to each other. once you know this then it should be clear where the given wave function comes from. i.e. a1=a3 and a2 = 0 and what the other possible eigenstates are.
 
Essentially what you are doing is what is commonly known as diagonalising the matrix. You should look up some basic linear algebra texts or even google to find out more about the details. The general idea in post #2 is correct, although some careless mistakes slipped in from line 4 onwards.
Give it a try and let us know if you face any further problems when trying to work them out.
 

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