A high diver jumping off a board (basic force problem)

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SUMMARY

The problem involves a high diver with a mass of 50.0 kg who jumps from a height of 10.0 m and is stopped by water in 2.30 seconds. The final velocity upon hitting the water is calculated to be 14 m/s using the equation vf² = v₀² + 2ax. The average acceleration during the deceleration phase is approximately 6.09 m/s², leading to a calculated force of 304.35 N. The initial calculation was marked incorrect, likely due to the expected convention of using a negative sign for upward acceleration.

PREREQUISITES
  • Understanding of Newton's second law (F=ma)
  • Knowledge of kinematic equations, specifically vf² = v₀² + 2ax
  • Basic concepts of forces and acceleration
  • Familiarity with the conventions of positive and negative directions in physics
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  • Review Newton's laws of motion and their applications in real-world scenarios
  • Study kinematic equations in-depth, focusing on their derivations and applications
  • Learn about the conventions of vector directions in physics problems
  • Explore the concept of average force and its calculation in various contexts
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Homework Statement



A high diver of mass 50.0 kg jumps off a board 10.0 m above the water. If her downward motion is stopped 2.30 s after she enters the water, what average force did the water exert on her?


Homework Equations



Fnet=ma
vf2=v02+2ax

The Attempt at a Solution



First I found the final velocity of the diver when she hits the water

vf2=02+2(9.8)(10)=196

vf=14 m/s

Since she is slowed to a stop in 2.3s the average acceleration would be

14/2.3 = 6.08696

Knowing acceleration and her mass, we can calculate the force.

F=50(6.08696)=304.348

This answer was marked wrong. I'm pretty sure I did everything right. Am I missing something?
 
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Your calculation is correct for the magnitude of the acceleration. Maybe the dumb machine that marked this problem expected a negative sign in front of the acceleration. I say "dumb" because the acceleration is in the "up" direction which is conventionally positive. You may have to ask your teacher for a clarification of this point.
 
Thanks for your input, I'll be sure to ask my professor about this problem.
 

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