A is n by n matrix. It is diagonalized by P. Find the matrix that

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The discussion confirms that if matrix A is diagonalized by matrix P, then the transpose of matrix A, denoted as A^t, is diagonalized by the transpose of P, denoted as P^t. The relationship is established through the equation A = PDP^-1, where D is the diagonal matrix of eigenvalues. The transpose of this equation leads to A^t = (P^t)^-1 * D * P^t, demonstrating that (P^t)^-1 diagonalizes A^t.

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A is n by n matrix. It is diagonalized by P. Find the matrix that diagonalizes the tranpose of A.


We have the equation A=PDP^-1
Where D is the diagonal matrix consisting of the eigen values of A.


(A)^t=(PDP^-1)^t
A^t=(P^-1)^t * D^t * P^t
A^t=(P^t)^-1 * D * P^t

So the matrix (P^t)^-1 diagonalizes A^t.

Is that correct?
 
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charlies1902 said:
A is n by n matrix. It is diagonalized by P. Find the matrix that diagonalizes the tranpose of A.


We have the equation A=PDP^-1
Where D is the diagonal matrix consisting of the eigen values of A.


(A)^t=(PDP^-1)^t
A^t=(P^-1)^t * D^t * P^t
A^t=(P^t)^-1 * D * P^t

So the matrix (P^t)^-1 diagonalizes A^t.

Is that correct?

Sounds fine to me.
 

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