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A little problem on dimensional analysis

  1. Nov 26, 2009 #1
    1. The problem statement, all variables and given/known data

    The dimensions for all sorts of energy must be equal.
    Then the following should hold:
    By E=Fs and E=VIt,
    [Fs] = [VIt]
    [M][L]2[T]-2=[V][Q]

    Now, according to some online lectures I watched some time ago, the dimensions of time, length, and mass are the three fundamental dimensions and all other dimensions can be derived with the three. So I was wondering if I could simplify the dimension of the p.d. and the coulomb into the three dimensions.

    Would appreciate any help. Thanks.
    Jeremy

    2. Relevant equations



    3. The attempt at a solution
    I asked my high school teacher the other day and he said that the dimensions for the coulomb and p.d. are already the simplest...
     
  2. jcsd
  3. Nov 26, 2009 #2

    rl.bhat

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    Homework Helper

    In an electric field F = E*Q
    And V = E*d
    Therefore Energy = V*Q = E*d*F/E = F*d.
     
  4. Nov 26, 2009 #3
    Oh. I didn't realise it was that simple. Thanks.
     
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