A Momentum-collision problem two dimensions (HELP)

AI Thread Summary
A clay ball of mass 6.20 kg is thrown at 22.0 m/s against a wall, breaking into three pieces after impact. The wall applies a force of 2660 N for 0.110 seconds. Two pieces, with masses of 2.20 kg and 1.20 kg, travel backward at specified velocities and angles. The discussion focuses on calculating the velocity and direction of the third piece after the collision. Key equations include momentum conservation and impulse-momentum relationships.
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Homework Statement



An m = 6.20-kg clay ball is thrown directly against a perpendicular brick wall at a velocity of 22.0 m/s and shatters into three pieces, which all fly backward, as shown in the figure. The wall exerts a force on the ball of 2660 N for 0.110 s. One piece of mass m1 = 2.20 kg travels backward at a velocity of 10.5 m/s and an angle of = 32.0° above the horizontal. A second piece of mass m2 = 1.20 kg travels at a velocity of 8.80 m/s and an angle of 28.0° below the horizontal.
a) What is the velocity of the third piece?
b) What is the direction of the third piece?

Homework Equations


P1i + P2i = P1f + P2f
I=Ft

The Attempt at a Solution

 
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