Assume an elastic collision (ignoring friction
and rotational motion).
A queue ball initially moving at 4.3 m/s
strikes a stationary eight ball of the same size
and mass. After the collision, the queue ball’s
final speed is 2.3 m/s .
Find the queue ball’s angle with respect
to its original line of motion.
v1i = 4.3
v1f = 2.3
p1i + p2i = p1f + p2f
KEi = KEf
The Attempt at a Solution
sqrt(4.3^2 - 2.3^2) = v2f = 3.6 m/s
4.3 = 2.3*cos θ + 3.6*cos φ (for x direction)
0 = 2.3*sin θ - 3.6*sin φ (for y direction)
2.3*sin θ = 3.6*sin φ
Not quite sure how to proceed from here.