A Penny Falling Off a Non-moving Sphere

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SUMMARY

The discussion focuses on the physics problem of a penny sliding off a fixed smooth sphere of radius 1 meter. The penny is released from rest and the objective is to determine how far it falls from the point of contact with the platform. Key equations discussed include the kinematic equations for motion under gravity and the conservation of energy principle to find the penny's speed at the point of departure from the sphere. The solution involves calculating the angle at which the penny leaves the sphere and applying forces to determine the distance fallen.

PREREQUISITES
  • Understanding of kinematic equations, specifically V = Vo + at and V^2 = Vo^2 + 2a(x - xo)
  • Knowledge of gravitational acceleration, specifically g = 9.8 m/s²
  • Familiarity with the concept of conservation of energy in physics
  • Ability to analyze forces acting on an object in motion
NEXT STEPS
  • Study the application of conservation of energy in dynamic systems
  • Learn about the forces acting on objects in circular motion
  • Explore the concept of projectile motion to understand the penny's trajectory after leaving the sphere
  • Investigate the role of angles in determining the motion of objects on curved surfaces
USEFUL FOR

Students studying physics, particularly those focused on mechanics, as well as educators looking for examples of real-world applications of kinematics and energy conservation principles.

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Homework Statement



A penny is released from the top of a very smooth sphere of radius 1 m. The sphere is fixed to a platform and doesn't move. The penny slides down from rest and leaves the sphere at a certain point. How far will the penny fall away from the point of contact of the sphere and the platform?

Homework Equations



(1) V = Vo + at
(2) a = (V^2)/9.8
(3) V^2 = Vo^2 + 2a(x - xo)

The Attempt at a Solution



Vo = 0 m/s
r = 1 m
a = g = 9.8 m/(s^2)
x = ? => The distance the penny fell from the top of the sphere to ground.

I used (1) in order to rearrange into

t = V/g

After doing that, I was thinking that maybe I could use (2) or (3) to rearrange the equation a little more to find the solution, but I'm sure that's not right, and I'm doing too much work. I've attached a pdf of the problem.
 

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Juan42 said:
(1) V = Vo + at
That's only valid for constant acceleration, which this is not. You need to find the point at which the penny leaves the sphere. Suppose the radius to that point makes an angle theta to the vertical. Use conservation of energy to find its speed there, then consider the forces on the penny at that point.
 

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