A penny is released from the top of a very smooth sphere of radius 1 m. The sphere is fixed to a platform and doesn't move. The penny slides down from rest and leaves the sphere at a certain point. How far will the penny fall away from the point of contact of the sphere and the platform?
(1) V = Vo + at
(2) a = (V^2)/9.8
(3) V^2 = Vo^2 + 2a(x - xo)
The Attempt at a Solution
Vo = 0 m/s
r = 1 m
a = g = 9.8 m/(s^2)
x = ? => The distance the penny fell from the top of the sphere to ground.
I used (1) in order to rearrange into
t = V/g
After doing that, I was thinking that maybe I could use (2) or (3) to rearrange the equation a little more to find the solution, but I'm sure that's not right, and I'm doing too much work. I've attached a pdf of the problem.