A penny is released from the top of a very smooth sphere of radius 1.3 meters. The sphere is fixed to a platform and doesn't move. The penny slides down from rest and leaves the sphere at a certain point. How far will the penny fall away from the point of contact of the sphere and the platform?
The penny just kind of slides off on it's own, and what needs to be found is where exactly it leaves the surface of the sphere.
mgh = 1/2*m*(V^2)
h can be found using the angle.
The Attempt at a Solution
From the drawing I drew, I had the penny start from the top of the sphere and picked a spot where it falls off. I drew a line through the center of the sphere and the point where the penny falls off, but I'm at a bit of loss of where exactly to begin.