A person moves a full sam's club shopping cart mass=80.0 kg from rest

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SUMMARY

A person moves a full Sam's Club shopping cart with a mass of 80.0 kg from rest to a velocity of 1.30 m/s over a distance of 1.80 meters. The time required to accelerate the cart can be calculated using the formula \( t = \frac{v}{a} \), where \( a \) is the acceleration. The change in momentum is determined using the equation \( \Delta p = m \cdot \Delta v \). Additionally, the force exerted on the cart can be calculated using Newton's second law, \( F = m \cdot a \), and the force required to overcome friction is found using the coefficient of friction (0.40) and the normal force.

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  • Knowledge of friction and its coefficients
  • Basic algebra for solving equations
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Ereny
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a person moves a full sam's club shopping cart mass=80.0 kg from rest to a velocity of 1.30 m/s over a distance of 1.80 meters to secure a spot in check out line.

A. find the time required to get the cart moving from rest to 1.30 m/s?

B. Determine the change in the chart's momentum?

c. determine the magnitude of the force exerted on the cart by the person.

D. the result from part c ignores friction. if the shopping cart's coefficient of friction is .40 determine the force required by the person to move the cart. (recall the friction force = UFn)
 
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Hi Ereny! :wink:

Show us what you've tried, and where you're stuck, and then we'll know how to help! :smile:
 

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