A point charge inside infinite medium of dielectric

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SUMMARY

A point charge located within an infinite dielectric medium characterized by a relative permittivity (\(\epsilon_r\)) presents a unique problem in electrostatics. The electric field vector and potential function can be derived using Gauss' Law, specifically in terms of the displacement field (\(D\)). The relevant equations include \(D = \epsilon E + P\), where \(P\) is the polarization vector, and \(\epsilon = \epsilon_0 \epsilon_r\). The discussion emphasizes the importance of symmetry in selecting a Gaussian surface to simplify calculations.

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  • Understanding of electrostatics and electric fields
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  • Knowledge of dielectric materials and their properties
  • Proficiency in vector calculus and potential functions
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  • Study the application of Gauss' Law in dielectric materials
  • Learn about the relationship between electric displacement (\(D\)) and electric field (\(E\))
  • Explore the concept of polarization in dielectric materials
  • Investigate the mathematical derivation of electric fields in spherical symmetry
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Students and professionals in physics, electrical engineering, and materials science who are dealing with electrostatics and dielectric materials will benefit from this discussion.

Ready2GoXtr
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A point charge inside infinite dielectric material

1. The problem statement, all variables and given known data
A point charge is an infinite medium of dielectric material having a relative permittivity \epsilon<sub>r</sub>. <--- epsilon(sub r). Find the electric field vector and the potential function at any point in space, assuming that the potential is zero volts at infinity.

Homework Equations


D = \epsilon * E + P
P = \epsilon<sub>0</sub> * \chi<sub>e</sub> vector E
\epsilon[\tex] = \epsilon&lt;sub&gt;0&lt;/sub&gt; * \epsilon&lt;sub&gt;r&lt;/sub&gt;<br /> \chi&lt;sub&gt;e&lt;/sub&gt; = \epsilon&lt;sub&gt;r&lt;/sub&gt; - 1<br /> <br /> <br /> well its not letting me put it in right so I am going to enter them in with () next to them <br /> D(vector) = epsilon*E(vector) + P(vector)<br /> P(vector) = epsilon(sub 0)*chi(sub e)*E(vector)<br /> epsilon = epsilon(sub 0)*epsilon(sub r)<br /> chi(sub e) = epsilon(sub r) - 1<br /> Electric Field of Point Charge = k*q/r^2<br /> Electric Field of Sphere = q/(4*pi*epsilon(sub0)*r^2)<br /> <br /> <h2>The Attempt at a Solution</h2><br /> Im not quiet sure what my first step would be. I would think that a point charge inside a dielectric medium would have a reduced electric field, but it is infinite so wouldn&#039;t its electric field be nothing?
 
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Just use Gauss' Law for \textbf{D}...can you think of a Gaussian surface that will exploit the symmetry present?
 
what do you mean by exploit?
 
"Exploit" is just another word for "use"
 
I feel that a sphere represents a good shape.
 
Ready2GoXtr said:
I feel that a sphere represents a good shape.

Okay, but why? And where will the center of the sphere be?
 
The center of the sphere will be located on the point charge
 
so would my answer just be q/(4*pi*epsilon(sub0)*r^2)
?
 
Not quite...What is Gauss' Law in terms of \textbf{D}? Do you see why Gauss' Law in terms of \textbf{E} isn't helpful here?
 

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