A problem I should be able to solve :( (geometry) This is a random problem I discovered on the internet: If the area of a rectangle is diminished by 36%, what are the sides of the original rectangle if the sides of the diminished one are 36mm and 48mm? My answer: Let a and b be the original sides (not diminished). ab*0,64=1728, so ab=2700. We know that c/d = 36/48 = a/b = 3/4 so a = 3/4 b Now: 3/4 b*b = 2700 So b^2 = 3600 And then b = +- sqrt of 3600, but since we want distance the answer is b=60. Because a = 3/4 b, we get a = 3/4 * 60 = 45.