A problem I should be able to solve (geometry)

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Homework Help Overview

The discussion revolves around a geometry problem involving the area of a rectangle and its dimensions. The original poster presents a scenario where the area of a rectangle is reduced by 36%, and they seek to determine the original dimensions based on the dimensions of the diminished rectangle.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to establish a relationship between the original and diminished areas, using algebraic expressions to find the original dimensions. Some participants question the source of a specific value used in the calculations, while others verify the correctness of the original poster's final answers.

Discussion Status

The discussion is active, with participants engaging in clarifying the calculations and confirming the validity of the original poster's results. There is acknowledgment of differing answers from other sources, indicating a potential exploration of multiple interpretations.

Contextual Notes

Participants are navigating through the implications of the area reduction and the relationships between the sides of the rectangles, with some uncertainty regarding the correctness of the calculations presented.

silenzer
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A problem I should be able to solve :( (geometry)

This is a random problem I discovered on the internet:

If the area of a rectangle is diminished by 36%, what are the sides of the original rectangle if the sides of the diminished one are 36mm and 48mm?

My answer: Let a and b be the original sides (not diminished).

ab*0,64=1728, so ab=2700. We know that c/d = 36/48 = a/b = 3/4 so a = 3/4 b

Now: 3/4 b*b = 2700
So b^2 = 3600
And then b = +- sqrt of 3600, but since we want distance the answer is b=60.

Because a = 3/4 b, we get a = 3/4 * 60 = 45.
 
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Where did the 1728 come from?

Did you check your final answers? Doo they work?
 


OldEngr63 said:
Where did the 1728 come from?

From multiplying 36 by 48 to get the area. And your answer looks correct silenzer.
 


Okay, thanks. I saw a different answer elsewhere and therefore thought I was wrong. Thanks for the help.
 

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