A puck slides a total of 12m: Problem relating kinteic friction to Newton's law

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Homework Help Overview

The problem involves a puck sliding on a shuffleboard, covering a distance of 12 meters before stopping. It relates to kinetic friction and Newton's laws of motion, specifically focusing on determining the initial speed of the puck given the coefficient of kinetic friction.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to find the acceleration but encounters difficulties due to multiple unknowns, including initial speed and time. They express uncertainty about how to proceed without the mass of the puck to calculate the normal force.

Discussion Status

Some participants suggest using Newton's second law to find acceleration without needing the mass, indicating that it can be treated as a variable. Others provide equations to relate acceleration to the distance traveled and final speed, noting that the puck comes to rest after the given distance.

Contextual Notes

There is a lack of information regarding the mass of the puck, which complicates the calculations. The discussion reflects the constraints of the problem as posed in a homework context.

Kat11111
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Homework Statement



In a shuffleboard game, the puck slides a total of 12 m before coming to rest. If the coefficient of kinetic friction between the puck and board is 0.28, what was the initial speed of the puck?

Homework Equations


f=ma
fk=U*N
vf^2=v^2+2ad
a=delta v/t


The Attempt at a Solution



I tried to find the acceleration using the equation above but since I don't know the initial speed, I get 2 unknown. I tried to substitute a by delat v/t but I don't have time either. I don't have the mass of the puck either so I can't find the normal force. How can I start?
 
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Use Newton's 2nd law to find the acceleration. (You don't need the actual mass--just call it m.)
 
From Newton's law: you can find acceleration of puck.
P + Ff + N = ma

After find a, you will use this eq:
[tex]v^2 - v_0^2= 2as[/tex]

Because puck is at rest after going distance = 12m, v = 0. Plug a, then you get answer.
 
Thanks to both of you, I got it! I didn't see the masses canceled in the first equation.
 

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