A quesiton about multidimensional Fourier transform

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SUMMARY

The discussion centers on the multidimensional Fourier transform represented by the integral \(\int_{-\infty}^{\infty}d^{4}p \frac{exp( ip*k)}{p^{2}+a^{2}}\). The participants explore the implications of setting the cosine factor in the scalar product \(p*k\) to 1, which simplifies the integration over angular variables. It is established that a four-dimensional analog to spherical coordinates exists, where the differential takes the form \(p^3 dp dA\), with \(A\) representing the surface area of the four-dimensional unit sphere. The integration limits for \(p\) extend from 0 to infinity.

PREREQUISITES
  • Understanding of Fourier transforms in multiple dimensions
  • Familiarity with four-dimensional geometry and spherical coordinates
  • Knowledge of scalar products in vector calculus
  • Basic concepts of integration in higher dimensions
NEXT STEPS
  • Study the properties of the Fourier transform in four dimensions
  • Research the derivation and application of four-dimensional spherical coordinates
  • Learn about the integration techniques for angular variables in multidimensional calculus
  • Explore the implications of setting cosine factors in scalar products in higher-dimensional integrals
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Mathematicians, physicists, and engineers working with multidimensional Fourier transforms, as well as students studying advanced calculus and vector analysis.

zetafunction
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my question is the following

let be the Fourier transform [tex]\int_{-\infty}^{\infty}d^{4}p \frac{exp( ip*k)}{p^{2}+a^{2}}[/tex]

here [tex]p^{2}= p_{0}^{2}+p_{1}^{2}+p_{2}^{2}+p_{3}^{2}[/tex]

is the modulus of vector 'p' , here * means scalar product

for the scalar product i can use the definition [tex]p*k= |p|.|k|.cos(u)[/tex]

so ony the modulus appear, my question is if there is a way to set cos(u) =1 to get rid of the integration about angular variables, thanks
 
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There is (I don't know the form offhand) a 4 dimensional analog to spherical coordinates. Let p be the magnitude of (p1,p2,p3,p4). The differential will look like p3dpdA where A is the 4-d analog of surface area of the unit sphere. The A integral is over the 4-d unit sphere - includes the cos(u) factor. The p integral is from 0 to ∞.
 

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