A question about an odd function

1. Jan 27, 2008

transgalactic

2. Jan 27, 2008

Shooting Star

Very much so.

3. Jan 27, 2008

HallsofIvy

Staff Emeritus
No one suggested 0 as an answer for that problem! x2(1+ sin2007(x)) is definitely not an odd function!

In your original post, people first suggested you separate it, just as you did here, into
$$\int_{-1}^1 x^2(1+ sin^{2007}(x))dx= \int_{-1}^1 x^2 dx+ \int_{-1}^1 x^2 sin^{2007}(x) dx$$
It was only the second part that was odd and so gave a 0 result, just as you have.

Last edited: Jan 27, 2008