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A question about an odd function

  1. Jan 27, 2008 #1
  2. jcsd
  3. Jan 27, 2008 #2

    Shooting Star

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    Very much so.
     
  4. Jan 27, 2008 #3

    HallsofIvy

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    No one suggested 0 as an answer for that problem! x2(1+ sin2007(x)) is definitely not an odd function!

    In your original post, people first suggested you separate it, just as you did here, into
    [tex]\int_{-1}^1 x^2(1+ sin^{2007}(x))dx= \int_{-1}^1 x^2 dx+ \int_{-1}^1 x^2 sin^{2007}(x) dx[/tex]
    It was only the second part that was odd and so gave a 0 result, just as you have.
     
    Last edited: Jan 27, 2008
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