A question about an odd function

[transgalactic]

x^2 * [1+(sinx)^2007]dx

i solved it in a different way and i got a different answer
from what you seggested?? "0"

is it ok??

http://img142.imageshack.us/my.php?image=img8224vq0.jpg

 

[Shooting Star]

Very much so.

 

[HallsofIvy]

No one suggested 0 as an answer for that problem! x²(1+ sin²⁰⁰⁷(x)) is definitely not an odd function!

In your original post, people first suggested you separate it, just as you did here, into
\int_{-1}^1 x^2(1+ sin^{2007}(x))dx= \int_{-1}^1 x^2 dx+ \int_{-1}^1 x^2 sin^{2007}(x) dx
It was only the second part that was odd and so gave a 0 result, just as you have.