A question about contact forces and friction

Click For Summary
SUMMARY

The discussion centers on calculating the contact force (P) between two blocks (m1 and m2) on a table, influenced by applied force (F) and kinetic friction coefficients (μ1 and μ2). The participants emphasize the importance of drawing accurate free-body diagrams to identify internal and external forces. It is established that P is considered an external force for the purpose of analyzing the system. The equations of motion for both blocks are derived, highlighting the necessity of correctly applying Newton's second law (F = ma) and the kinetic friction formula (Kinetic force = μk x FN).

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Knowledge of free-body diagrams
  • Familiarity with kinetic friction concepts
  • Ability to apply equations of motion in physics
NEXT STEPS
  • Study the derivation of equations of motion for multiple bodies in contact
  • Learn about the implications of internal vs. external forces in system analysis
  • Explore advanced applications of kinetic friction in real-world scenarios
  • Review problem-solving techniques for physics homework involving forces and motion
USEFUL FOR

Students studying physics, particularly those focusing on mechanics, as well as educators looking for examples of force analysis in multi-body systems.

devilish_wit
Messages
16
Reaction score
0

Homework Statement


Two blocks of masses m1 and m2 are placed on a table in contact with each other as shown in the figure below. The coefficient of kinetic friction between the block of mass m1 and the table is μ1, and that between the block of mass m2 and the table is μ2. A horizontal force of magnitude F is applied to the block of mass m1. We wish to find P, the magnitude of the contact force between the blocks.
5-figure-12a.gif

Homework Equations



F = ma
Kinetic force = μk x FN

The Attempt at a Solution



I was pretty sure my answer for (d) was right. I'm not sure what I did wrong[/B]

upload_2018-10-8_19-6-37.png
 

Attachments

  • upload_2018-10-8_19-6-20.png
    upload_2018-10-8_19-6-20.png
    10.9 KB · Views: 733
  • upload_2018-10-8_19-6-37.png
    upload_2018-10-8_19-6-37.png
    12.9 KB · Views: 1,852
  • 5-figure-12a.gif
    5-figure-12a.gif
    2.3 KB · Views: 1,628
Physics news on Phys.org
Draw a free-body diagram for ##m_2##. What forces are directly acting on ##m_2##?
 
devilish_wit said:
I was pretty sure my answer for (d) was right. I'm not sure what I did wrong
You would have to tell us what you did before we can tell you what you did wrong. Can you tell us what you were thinking when you were "pretty sure" you'd done it correctly?

Note, by the way, that ##P## is an internal force.
 
Mister T said:
Note, by the way, that ##P## is an internal force.
Whether a force is "internal", "external", or irrelevant depends on where you have drawn the boundaries around the system of interest. For question d, I would draw the boundaries such that P is an external force.
 
Mister T said:
You would have to tell us what you did before we can tell you what you did wrong. Can you tell us what you were thinking when you were "pretty sure" you'd done it correctly?

Note, by the way, that ##P## is an internal force.

upload_2018-10-8_21-30-31.png


That's my free body diagram

For m1:

Fnet = F - P - μ1(N) ---> F - (μ1m1)g - P

For m2: (I'm not sure if F is still included in this equation or not?)

Fnet = F + P - μ2(N) ---> F - (μ2m2)g + P (this answer was wrong)
 

Attachments

  • upload_2018-10-8_21-30-31.png
    upload_2018-10-8_21-30-31.png
    6.4 KB · Views: 1,231
jbriggs444 said:
Whether a force is "internal", "external", or irrelevant depends on where you have drawn the boundaries around the system of interest. For question d, I would draw the boundaries such that P is an external force.

Is my free body diagram correct?
upload_2018-10-8_21-30-31-png.png
 

Attachments

  • upload_2018-10-8_21-30-31-png.png
    upload_2018-10-8_21-30-31-png.png
    6.4 KB · Views: 1,096
devilish_wit said:
Is my free body diagram correct?
Yes, that looks correct.
 

Similar threads

  • · Replies 17 ·
Replies
17
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 13 ·
Replies
13
Views
6K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 14 ·
Replies
14
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
Replies
13
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K